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c++,new,delete,成员指针

new和delete用来申请动态内存空间,一定要配对使用

#include <string>    #include <ctype.h>#include <vector>#include <iostream>  #include <fstream>// using declarations states our intent to use these names from the namespace std    using namespace  std;int main(){    int *p = static_cast<int*>(malloc(sizeof(int)));     //对于内置类型,如int,double,float,char...即使不用new声明,使用delete释放也不会出任何编译,运行错误,但是对于任何类类型,不管是自定义还是系统自带的,都会出错误    int *p_new = new int; //分配一个int类型的地址空间,不进行初始化    int *p_new_1 = new int(10);//初始化为10    int n = 10;//如果n过大,会导致内存申请失败抛出错误,如果不想抛出错误可以再new后面加上nothrow
//为什么说是动态分配内存,因为n是变量,是不确定的,所以每次分配的内存不确定,是在运行时分配
char *p_new_array = new(nothrow) char[n];//对于内置类型,n为0时这样写没问题,而且可以进行解引用,并且直接delete不用数组括号也行 string *p_new_string = new string[n];//n为0时无法进行解引用,会报错,不加括号的delete出错,也不能进行解引用。 cout << *p << endl; cout << *p_new << endl; cout << *p_new_1 << endl; cout << *p_new_array << *(p_new_array+1) << endl; //delete p;// 基本内置类型可以,对于类类型这样不行,因为不是用new声明的 delete p_new;p_new=null;//将悬空指针变为空指针 delete p_new_1; p_new_1=null; delete p_new_array; p_new_array=null;//错误的写法,只对基本内置类型有效 delete[]p_new_string; //正确的写法,要和相应的new配对 return 0;}

 

成员地址,是相对于开始地址的相对偏移。

#include <string>    #include <ctype.h>#include <vector>#include <iostream>  #include <fstream>#include<new>// using declarations states our intent to use these names from the namespace std    using namespace  std;struct Date{    int year;    int month;    int day;    void print(){ cout << year << "-" << month << "-" << day << endl; }};void showYear(Date a[], int length, int Date::*year);int main(){    Date a[5] = { { 2001, 1, 1 }, { 2002, 2, 2 }, { 2003, 3, 3 }, { 2004, 4, 4 }, { 2005, 5, 5 } };    Date d = { 1997, 7, 9 };    cout << "&d = " << &d << endl;    cout << "&d.year = " << &d.year << " &d.month = " << &d.month << " &d.day =" << &d.day << endl; //绝对地址    cout << &Date::year << &Date::month << &Date::day << endl;//成员地址打印出来是111,c++认为成员地址和函数地址无意义,所以都直接处理为true,在输出也就显示为1    //cout << static_cast<int*>(&Date::year) << endl; //那么,强转来看看地址,结果报错,不能转换    //匿名联合,两个变量同用同一个空间    union     {        int n;        int Date::*mp;    };    mp = &Date::day;    cout << "n = " << n << endl;//输出8,相对于year的地址    //通过成员地址来访问结构中的成员    cout << d.*mp << endl;    //应用,访问a数组中的,所有日期中的年份    showYear(a, sizeof(a)/sizeof(Date), &Date::year);    //成员函数指针    d.print();    void (Date::*p)() = &Date::print;    (d.*p)();    return 0;}void showYear(Date a[], int length, int Date::*p)//p是date中某个成员的地址,不可用day,year,month,会造成表达模糊{    for (int i = 0; i < length;++i)    {        cout << a[i].*p << " "; //a[i].year表达不出我想要用成员地址的意愿,因为year本来就是成员        //p是成员地址,*p是结构中的某个成员,a[i].*p,取出这个成员    }    cout << endl;}