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python函数

2024-08-28 23:47:43   221人阅读

set 添加一个无序的，用set方法，访问速度快，天生解决了重复问题

1、difference 指定某个元素从原来set取出，并生成新的set

1 #difference
2 a = set(["aaa","bbb","ccc","aaa"])
3 print(a)
4 b = a.difference(["aaa"])
5 print(b)
6 
7 {‘ccc‘, ‘bbb‘, ‘aaa‘}
8 {‘ccc‘, ‘bbb‘}

 

2、difference_update 删除原来set里某个元素

 1 #difference_update
 2 a = set(["aaa","bbb","ccc","aaa"])
 3 print(a)
 4 b = a.difference_update(["aaa"])
 5 print(a)
 6 print(b)
 7 
 8 
 9 {‘bbb‘, ‘ccc‘, ‘aaa‘}
10 {‘bbb‘, ‘ccc‘}
11 None

 

 

3、pop 删除某个元素

 1 #pop
 2 a = set(["aaa","bbb","ccc","aaa"])
 3 print(a)
 4 b = a.pop()
 5 print(a)
 6 print(b)
 7 
 8 
 9 {‘aaa‘, ‘bbb‘, ‘ccc‘}
10 {‘bbb‘, ‘ccc‘}
11 aaa

 

 

4、remove 删除指定元素

 1 #remove
 2 a = set(["aaa","bbb","ccc","aaa"])
 3 print(a)
 4 b = a.remove("ccc")
 5 print(a)
 6 print(b)
 7 
 8 
 9 {‘bbb‘, ‘ccc‘, ‘aaa‘}
10 {‘bbb‘, ‘aaa‘}
11 None

 

 

这里举一个例子，更新、删除、添加原来的表

 1 old_dict = {
 2     "#1": {‘hostname‘: ‘c1‘, ‘cpu_count‘: 2, ‘mem_capicity‘: 80},
 3     "#2": {‘hostname‘: ‘c1‘, ‘cpu_count‘: 2, ‘mem_capicity‘: 80},
 4     "#3": {‘hostname‘: ‘c1‘, ‘cpu_count‘: 2, ‘mem_capicity‘: 80}
 5 }
 6 # cmdb 新汇报的数据
 7 new_dict = {
 8     "#1": {‘hostname‘: ‘c1‘, ‘cpu_count‘: 2, ‘mem_capicity‘: 800},
 9     "#3": {‘hostname‘: ‘c1‘, ‘cpu_count‘: 2, ‘mem_capicity‘: 80},
10     "#4": {‘hostname‘: ‘c2‘, ‘cpu_count‘: 2, ‘mem_capicity‘: 80}
11 }
12 
13 a = set(old_dict.keys())
14 b = set(new_dict.keys())
15 
16 #要更新的数据
17 update_set = a.intersection(b)
18 print(update_set)
19 #要删除的数据
20 delete_set = a.symmetric_difference(update_set)
21 print(delete_set)
22 #要添加的数据
23 add_set = b.symmetric_difference(update_set)
24 print(add_set)
25 
26 
27 
28 {‘#3‘, ‘#1‘}
29 {‘#2‘}
30 {‘#4‘}

 

python函数


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