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237.单链表移除节点 Delete Node in a Linked List
Question
Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is
1 -> 2 -> 3 -> 4
and you are given the third node with value3
, the linked list should become1 -> 2 -> 4
after calling your function.
Solution
Approach: Swap with Next Node [Accepted]
The usual way of deleting a node node
from a linked list is to modify the next
pointer of the node before it, to point to the node after it.
Since we do not have access to the node before the one we want to delete, we cannot modify the next
pointer of that node in any way. Instead, we have to replace the value of the node we want to delete with the value in the node after it, and then delete the node after it.
Because we know that the node we want to delete is not the tail of the list, we can guarantee that this approach is possible.
public void DeleteNode(ListNode node) {
node.val = node.next.val;
node.next = node.next.next;
}
237.单链表移除节点 Delete Node in a Linked List