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LeetCode OJ - Minimum && Maximum Depth of Binary Tree
这两道题用递归的解法都很简单,只是稍有不同。
下面是AC代码:
1 /** 2 * Given a binary tree, find its minimum depth. 3 * the minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 4 * @param root 5 * @return 6 */ 7 public int minDepth(TreeNode root){ 8 //the boundary condition 9 if(root == null) 10 return 0; 11 return minDepthRec(root); 12 } 13 private int minDepthRec(TreeNode root){ 14 if(root == null) 15 return 0; 16 if(root.left == null && root.right == null) 17 return 1; 18 //the condition judged here is very important here 19 if(root.left == null) 20 return minDepthRec(root.right)+1; 21 if(root.right == null) 22 return minDepthRec(root.left)+1; 23 return Math.min(minDepthRec(root.left), minDepthRec(root.right))+1; 24 }
1 /** 2 * Given a binary tree, find its maximum depth. 3 * The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 4 * @param root 5 * @return 6 */ 7 public int maxDepth(TreeNode root){ 8 if(root == null) 9 return 0; 10 if(root.left == null && root.right == null) 11 return 1; 12 return Math.max(maxDepth(root.left), maxDepth(root.right))+1; 13 }
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