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Binary Tree Zigzag Level Order Traversal
Given a binary tree, return the zigzag level order traversal of its nodes‘ values. (ie, from left to right, then right to left for the next level and alternate between).
For example:
Given binary tree [3,9,20,null,null,15,7]
,
3 / 9 20 / 15 7
return its zigzag level order traversal as:
[ [3], [20,9], [15,7] ]
分析: 层序遍历的,注意Zigzag的顺序
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector<vector<int>> zigzagLevelOrder(TreeNode* root) { vector<vector<int>> res; if(root == NULL) return res; queue<TreeNode* > nodesQue; bool flag = true; nodesQue.push(root); while(!nodesQue.empty()){ int size = nodesQue.size(); vector<int> temp(size,0); for(int i=0; i<size;i++){ TreeNode* node = nodesQue.front(); nodesQue.pop(); int index = flag? i: size-1-i; temp[index] = node->val; if(node->left) nodesQue.push(node->left); if(node->right) nodesQue.push(node->right); } flag = !flag; res.push_back(temp); } return res; } };
Binary Tree Zigzag Level Order Traversal
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