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Single Number
Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
1 class Solution { 2 public: 3 int singleNumber(int A[], int n) { 4 5 unordered_map<int, int> singleMap; 6 for(int i = 0; i < n; i++) 7 { 8 if(singleMap.find(A[i]) != singleMap.end()) 9 singleMap[ A[i] ]++;10 else11 singleMap[ A[i] ] = 1;12 }13 14 for(unordered_map<int, int>::iterator it = singleMap.begin(); it != singleMap.end(); it++)15 {16 if(it->second != 2)17 return it->first;18 }19 }20 };
Single Number
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