1. 获取解析文件路径
    NSString * xmlPath = [[NSBundle mainBundle] pathForResource:@"Person" ofType:@"xml"];

2.初始化xml字符串
     NSString * xmlStr = [NSString stringWithContentsOfFile:xmlPath encoding:NSUTF8StringEncoding error:nil];

3.初始化一个GDataXMLDocument对象 , 因为解析时所有的内容都是从该对象中获取,(所以需要将要解析的内容放入该对象)
     GDataXMLDocument * document = [[GDataXMLDocument alloc]initWithXMLString:xmlStr options:0 error:nil];
 
    XPath 只要给定相对路径即可比如: //name .只要能到达name,都可以把name获取
    获取所有的name节点
         NSArray * nameElement = [document nodesForXPath:@"//name" error:nil];
    获取所有gender节点
         NSArray * genderElement = [document nodesForXPath:@"//gender" error:nil];

通过循环取出每个节点

 for (int i = 0; i < 3; i ++) {
     GDataXMLElement * nameEle = nameElement[i];
     GDataXMLElement * genderEle = genderElement[i];

    取节点属性中的字符串
     NSString * a = [[nameEle attributeForName:@"name"] stringValue];

    取节点字符串
     NSString * name = [nameEle stringValue];
     NSLog(@"aaa      ddddd%@",a);
 }

XML解析 DOM(2)