import java.util.Calendar;public class CertNoUtil {    public static boolean vIDNumByRegex(String idNum) {        String curYear = "" + Calendar.getInstance().get(Calendar.YEAR);        int y3 = Integer.valueOf(curYear.substring(2, 3));        int y4 = Integer.valueOf(curYear.substring(3, 4));        // 43 0103 1973 0 9 30 051 9        return idNum.matches("^(1[1-5]|2[1-3]|3[1-7]|4[1-6]|5[0-4]|6[1-5]|71|8[1-2])\\d{4}(19\\d{2}|20([0-" + (y3 - 1) + "][0-9]|" + y3 + "[0-" + y4                + "]))(((0[1-9]|1[0-2])(0[1-9]|[1-2][0-9]|3[0-1])))\\d{3}([0-9]|x|X)$");        // 44 1825 1988 0 7 1 3 003 4    }    private static int ID_LENGTH = 17;    public static boolean vIDNumByCode(String idNum) {        // 系数列表        int[] ratioArr = {7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2};        // 校验码列表        char[] checkCodeList = {‘1‘, ‘0‘, ‘X‘, ‘9‘, ‘8‘, ‘7‘, ‘6‘, ‘5‘, ‘4‘, ‘3‘, ‘2‘};        // 获取身份证号字符数组        char[] cIds = idNum.toCharArray();        // 获取最后一位（身份证校验码）        char oCode = cIds[ID_LENGTH];        int[] iIds = new int[ID_LENGTH];        int idSum = 0;// 身份证号第1-17位与系数之积的和        int residue = 0;// 余数(用加出来和除以11，看余数是多少？)        for (int i = 0; i < ID_LENGTH; i++) {            iIds[i] = cIds[i] - ‘0‘;            idSum += iIds[i] * ratioArr[i];        }        residue = idSum % 11;// 取得余数        return Character.toUpperCase(oCode) == checkCodeList[residue];    }    public static boolean vId(String idNum) {        return vIDNumByCode(idNum) && vIDNumByRegex(idNum);    }    public static void main(String[] args) {        String idNum = "430103197309300519";        System.out.println(vId(idNum));    }}