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Letter Combinations of a Phone Number

Given a digit string, return all possible letter combinations that the number could represent.

A mapping of digit to letters (just like on the telephone buttons) is given below.

Input:Digit string "23"Output: ["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"].

Note:
Although the above answer is in lexicographical order, your answer could be in any order you want.

 

主要是建立数字字母映射表,然后依次对每个数字所对应的字母进行深搜,代码如下:

 1 class Solution { 2 public: 3     vector<string> letterCombinations(string digits) { 4         vector<string> vstr(9); //建立数字映射字母表 5         char ch = a; 6         for(int i=1; i<9; ++i) { 7             if( i == 6 || i == 8) { 8                 int cnt = 4; 9                 while( cnt-- ) vstr[i].push_back(ch++);10             }11             else {12                 int cnt = 3;13                 while( cnt-- ) vstr[i].push_back(ch++);14             }15         }16         ans.clear();17         string str;18         dfs(digits, vstr, 0, str);  //深搜19         return ans;20     }21     22     void dfs(string& digits, vector<string>& vstr, int k, string& str) {23         if( k == digits.length() ) {    //如果搜到了末尾,str就是答案之一24             ans.push_back(str);25             return;26         }27         int index = digits[k]-0-1;    //取对应数字在映射表中的位置28         for(int i=0; i<vstr[index].size(); ++i) {   //对每个数字所代表字母的进行深搜29             str.push_back(vstr[index][i]);30             dfs(digits, vstr, k+1, str);31             str.pop_back();32         }33     }34     35 private:36     vector<string> ans;37 };

 

Letter Combinations of a Phone Number