首页 > 代码库 > String to Integer (atoi)
String to Integer (atoi)
Implement atoi to convert a string to an integer.
Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases.
Notes: It is intended for this problem to be specified vaguely (ie, no given input specs). You are responsible to gather all the input requirements up front.
思路:
1 class Solution { 2 public: 3 int atoi( const char *str ) { 4 double ret = 0, sign = 1.0; 5 while( *str != ‘\0‘ && *str == ‘ ‘ ) { ++str; } 6 if( *str == ‘+‘ || *str == ‘-‘ ) { sign = *(str++) == ‘+‘ ? 1.0 : -1.0; } 7 while( *str >= ‘0‘ && *str <= ‘9‘ ) { 8 ret = 10*ret + sign*( *(str++)-‘0‘ ); 9 }10 if( ret > INT_MAX ) { return INT_MAX; }11 if( ret < INT_MIN ) { return INT_MIN; }12 return (int)ret;13 }14 };
String to Integer (atoi)
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。