select number from master..spt_values with(nolock) where type=‘P‘/**解释:master..spt_values表的字段值为P的对应number字段值是从0-2047*/     --1.将字符串转换为列显示   if object_id(‘tb‘) is not null drop table tb go create table tb([编号] varchar(3),[产品] varchar(2),[数量] int,[单价] int,[金额] int,[序列号] varchar(8)) insert into tb([编号],[产品],[数量],[单价],[金额],[序列号]) select ‘001‘,‘AA‘,3,5,15,‘12,13,14‘ union allselect ‘002‘,‘BB‘,8,9,13,‘22,23,24‘go select [编号],[产品],[数量],[单价],[金额] ,substring([序列号],b.number,charindex(‘,‘,[序列号]+‘,‘,b.number)-b.number) as [序列号] from tb a with(nolock),master..spt_values b with(nolock) where b.number>=1 and b.number<len(a.[序列号]) and b.type=‘P‘and substring(‘,‘+[序列号],number,1)=‘,‘go drop table tb go /** 编号   产品   数量          单价          金额          序列号 ---- ---- ----------- ----------- ----------- -------- 001  AA   3           5           15          12 001  AA   3           5           15          13 001  AA   3           5           15          14 002  BB   8           9           13          22 002  BB   8           9           13          23 002  BB   8           9           13          24 */ ----------   --2.第四个逗号之前的字符串 declare @str varchar(100) set @str=‘10,102,10254,103265,541,2154,41,156‘;with cte as( select left(@str,number-1) as ss,row_number()over(order by getdate()) as xh from master..spt_values with(nolock)  where number>=1 and number<=len(@str+‘,‘) and type=‘P‘ and substring(@str+‘,‘,number,1)=‘,‘)select ss from cte where xh=4 /** ss ------------------- 10,102,10254,103265 */ ----------     --3.找出两句话中相同的汉字 declare @Lctext1 varchar(100) declare @Lctext2 varchar(100) set @Lctext1=‘我们都是来自五湖四海的朋友‘set @Lctext2=‘朋友多了路真的好走吗‘select substring(@Lctext2,number,1) as value from master..spt_values with(nolock) where type=‘P‘ and number>=1 and number<=len(@Lctext2) and charindex(substring(@Lctext2,number,1),@Lctext1,number)>1 /** value ----- 朋 友 的 */ ---------     --4.提取两个日期之间的所有月份 if object_id(‘tb‘) is not null drop table tb go create table tb(id int identity(1,1),startDate varchar(10),endDate varchar(10)) insert into tb(startDate,endDate) select ‘2013-01-01‘,‘2013-09-25‘go declare @startDate varchar(10) declare @endDate varchar(10) select @startDate=startDate,@endDate=endDate from tb with(nolock) select convert(varchar(7),dateadd(mm,number,@startDate),120) as [月份] from master..spt_values with(nolock) where type=‘P‘ and number>=0 and dateadd(mm,number,@startDate)<=@endDate go drop table tb go /** 月份 ------- 2013-01 2013-02 2013-03 2013-04 2013-05 2013-06 2013-07 2013-08 2013-09 */ ---------     --5.求一个日期所在月份的所有日期 declare @date datetime set @date=‘2013-08-31‘select convert(char(7),@date,120)+‘-‘+right(‘0‘+convert(varchar(2),number),2) as [日期格式1] ,ltrim(year(@date))+right(100+month(@date),2)+right(‘0‘+ltrim(number),2) as [日期格式2] from master..spt_values with(nolock) where type=‘P‘ and number>=1 --and number<=datediff(dd,@date,dateadd(mm,1,@date)) --对于mssql而言该语句不试用于2013-08-31的情况，这时由于9月没有31号，固计算出来的天数是30天 and number<=datediff(dd,convert(char(7),@date,120)+‘-01‘,convert(char(7),dateadd(mm,1,@date),120)+‘-01‘)--转换为1号来计算天数 /** 日期格式1       日期格式2 ----------- -------------------- 2013-08-01  20130801 2013-08-02  20130802 2013-08-03  20130803 2013-08-04  20130804 2013-08-05  20130805 2013-08-06  20130806 2013-08-07  20130807 2013-08-08  20130808 2013-08-09  20130809 2013-08-10  20130810 2013-08-11  20130811 2013-08-12  20130812 2013-08-13  20130813 2013-08-14  20130814 2013-08-15  20130815 2013-08-16  20130816 2013-08-17  20130817 2013-08-18  20130818 2013-08-19  20130819 2013-08-20  20130820 2013-08-21  20130821 2013-08-22  20130822 2013-08-23  20130823 2013-08-24  20130824 2013-08-25  20130825 2013-08-26  20130826 2013-08-27  20130827 2013-08-28  20130828 2013-08-29  20130829 2013-08-30  20130830 2013-08-31  20130831 */ ---------     --6.根据给定时间为基准以2小时为划分，得出一天划分出的时间段 declare @time varchar(5) set @time=‘11:13‘select ltrim(a.number)+right(@time,3)+‘-‘+ltrim(b.number)+right(@time,3) as [划分结果] from master..spt_values a with(nolock),master..spt_values b with(nolock) where a.type=‘P‘ and b.type=‘P‘and a.number>=left(@time,2) and b.number<=24 and a.number+2=b.number /** 划分结果 ----------------------------------- 11:13-13:13 12:13-14:13 13:13-15:13 14:13-16:13 15:13-17:13 16:13-18:13 17:13-19:13 18:13-20:13 19:13-21:13 20:13-22:13 21:13-23:13 22:13-24:13 */ ---------     --7.将字符串显示为行列 if object_id(‘tb‘) is not null drop table tb create table tb(id int identity(1,1),s nvarchar(100)) insert into tb(s) select ‘车位地址1,车位状况1|车位地址2,车位状况2|车位地址n,车位状况n‘;with cte as( select substring(s,number,charindex(‘|‘,s+‘|‘,number)-number) as ss from tb with(nolock),master..spt_values with(nolock) where type=‘P‘ and number>=1 and number<=len(s) and substring(‘|‘+s,number,1)=‘|‘)select left(ss,charindex(‘,‘,ss)-1)as s1,substring(ss,charindex(‘,‘,ss)+1,len(ss))as s2 from cte drop table tb /** s1             s2 ----------- ------------ 车位地址1      车位状况1 车位地址2      车位状况2 车位地址n      车位状况n */