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关于json解析的几种方法
parse用于从一个字符串中解析出json对象,如
var
str =
‘{"name":"huangxiaojian","age":"23"}‘
注意:单引号写在{}外,每个属性名都必须用双引号,否则会抛出异常。
JSON.parse(jsonString): 在一个字符串中解析出JSON对象
var
str =
‘[{"href":"baidu.com","text":"test","orgId":123,"dataType":"curry","activeClass":"haha"}]‘
;
JSON.parse(str);
/*---------------------------------------------------------------------------------*/
2、JSON.stringify(obj) : 将一个JSON对象转换成字符串
var
obj = [{
"href"
:
"baidu.com"
,
"text"
:
"test"
,
"orgId"
:123,
"dataType"
:
"curry"
,
"activeClass"
:
"haha"
}];
JSON.stringify(obj);
"[{"
href
":"
baidu.com
","
text
":"
test
","
orgId
":123,"
dataType
":"
curry
","
activeClass
":"
haha
"}]"
/*---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------*/
3、jQuery.parseJSON(jsonString) : 将格式完好的JSON字符串转为与之对应的JavaScript对象
var
str =
‘[{"href":"baidu.com","text":"test","orgId":123,"dataType":"curry","activeClass":"haha"}]‘
;
jQuery.parseJSON(str);
/*---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------*/
4、JSON.parse()和jQuery.parseJSON()的区别:
有的浏览器不支持JSON.parse()方法,使用jQuery.parseJSON()方法时,在浏览器支持时会返回执行JSON.parse()方法的结果,否则会返回类似执行eval()方法的结果,以上结论参考jquery 1.9.1 得出:
parseJSON:
function
( data ) {
// Attempt to parse using the native JSON parser first
if
( window.JSON && window.JSON.parse ) {
return
window.JSON.parse( data );
}
if
( data =http://www.mamicode.com/==
null
) {
return
data;
}
if
(
typeof
data =http://www.mamicode.com/==
"string"
) {
// Make sure leading/trailing whitespace is removed (IE can‘t handle it)
data = http://www.mamicode.com/jQuery.trim( data );
if
( data ) {
// Make sure the incoming data is actual JSON
// Logic borrowed from http://json.org/json2.js
if
( rvalidchars.test( data.replace( rvalidescape,
"@"
)
.replace( rvalidtokens,
"]"
)
.replace( rvalidbraces,
""
)) ) {
return
(
new
Function(
"return "
+ data ) )();
}
}
}
jQuery.error(
"Invalid JSON: "
+ data );
},
/*---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------*/
/*---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------*/
关于json解析的几种方法