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leetcode - Binary Tree Preorder Traversal
Given a binary tree, return the preorder traversal of its nodes‘ values.
For example:
Given binary tree {1,#,2,3}
,
1 2 / 3
return [1,2,3]
.
Note: Recursive solution is trivial, could you do it iteratively?
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ //BinTree的先序遍历 struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode(int x): val(x), left(NULL),right(NULL) {} } class Solution { public: std::vector<int> preorderTraversal(TreeNode *root) { std::vector<int> vec; BinTree(root,vec); return vec; } void BinTree(TreeNode *root, std::vector<int> &vec) { if(root != NULL) { vec.push_back(root->vel); BinTree(root->left,vec); BinTree(root->right,vec); } } };
leetcode - Binary Tree Preorder Traversal
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