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判断字符串里是否有表情
刚遇到一个需求,发的字符里面不能有表情,下面是实现方法:
/** * 判断文字里面是否包含表情 */- (BOOL)isContainsEmoji:(NSString *)string { __block BOOL isEomji = NO; [string enumerateSubstringsInRange:NSMakeRange(0, [string length]) options:NSStringEnumerationByComposedCharacterSequences usingBlock: ^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) { const unichar hs = [substring characterAtIndex:0]; if (0xd800 <= hs && hs <= 0xdbff) { if (substring.length > 1) { const unichar ls = [substring characterAtIndex:1]; const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000; if (0x1d000 <= uc && uc <= 0x1f77f) { isEomji = YES; } } } else if (substring.length > 1) { const unichar ls = [substring characterAtIndex:1]; if (ls == 0x20e3) { isEomji = YES; } } else { if (0x2100 <= hs && hs <= 0x27ff && hs != 0x263b) { isEomji = YES; } else if (0x2B05 <= hs && hs <= 0x2b07) { isEomji = YES; } else if (0x2934 <= hs && hs <= 0x2935) { isEomji = YES; } else if (0x3297 <= hs && hs <= 0x3299) { isEomji = YES; } else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50|| hs == 0x231a ) { isEomji = YES; } } }]; return isEomji;}
判断字符串里是否有表情
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