首页 > 代码库 > Binary Tree Inorder Traversal
Binary Tree Inorder Traversal
1. Recursive
Straight Forward, Add left -> root -> right
/** * Definition of TreeNode: * public class TreeNode { * public int val; * public TreeNode left, right; * public TreeNode(int val) { * this.val = val; * this.left = this.right = null; * } * } */ public class Solution { /** * @param root: The root of binary tree. * @return: Inorder in ArrayList which contains node values. */ public ArrayList<Integer> inorderTraversal(TreeNode root) { // write your code here ArrayList<Integer> rst = new ArrayList<Integer>(); if(root == null) { return rst; } traversal(rst, root); return rst; } private void traversal(ArrayList<Integer> rst, TreeNode root) { if (root == null) { return; } traversal(rst, root.left); rst.add(root.val); traversal(rst, root.right); } }
2. Iterator
1. Create a node to present current node.
2. If current node is not null and stack is not empty
1) keep adding all the left child to the stack.
2) move the current node to the top of the stack
3) pop the top node and add it to the result list
4) let the current node to be the right child.
/** * Definition of TreeNode: * public class TreeNode { * public int val; * public TreeNode left, right; * public TreeNode(int val) { * this.val = val; * this.left = this.right = null; * } * } */ public class Solution { /** * @param root: The root of binary tree. * @return: Inorder in ArrayList which contains node values. */ public ArrayList<Integer> inorderTraversal(TreeNode root) { // write your code here ArrayList<Integer> rst = new ArrayList<Integer>(); Stack<TreeNode> stack = new Stack<TreeNode>(); TreeNode curNode = root; while (curNode != null || !stack.empty()) { //reach deepest left child while (curNode != null) { stack.push(curNode); curNode = curNode.left; } curNode = stack.peek(); stack.pop(); rst.add(curNode.val); curNode = curNode.right; } return rst; } }
Binary Tree Inorder Traversal
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。