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Pandas -- Merge,join and concatenate
Merge, join, and concatenate
pandas provides various facilities for easily combining together Series, DataFrame, and Panel objects with various kinds of set logic for the indexes and relational algebra functionality in the case of join / merge-type operations.
Concatenating objects
The concat
function (in the main pandas namespace) does all of the heavy lifting of performing concatenation operations along an axis while performing optional set logic (union or intersection) of the indexes (if any) on the other axes. Note that I say “if any” because there is only a single possible axis of concatenation for Series.
Before diving into all of the details of concat
and what it can do, here is a simple example:
In [1]: df1 = pd.DataFrame({‘A‘: [‘A0‘, ‘A1‘, ‘A2‘, ‘A3‘], ...: ‘B‘: [‘B0‘, ‘B1‘, ‘B2‘, ‘B3‘], ...: ‘C‘: [‘C0‘, ‘C1‘, ‘C2‘, ‘C3‘], ...: ‘D‘: [‘D0‘, ‘D1‘, ‘D2‘, ‘D3‘]}, ...: index=[0, 1, 2, 3]) ...: In [2]: df2 = pd.DataFrame({‘A‘: [‘A4‘, ‘A5‘, ‘A6‘, ‘A7‘], ...: ‘B‘: [‘B4‘, ‘B5‘, ‘B6‘, ‘B7‘], ...: ‘C‘: [‘C4‘, ‘C5‘, ‘C6‘, ‘C7‘], ...: ‘D‘: [‘D4‘, ‘D5‘, ‘D6‘, ‘D7‘]}, ...: index=[4, 5, 6, 7]) ...: In [3]: df3 = pd.DataFrame({‘A‘: [‘A8‘, ‘A9‘, ‘A10‘, ‘A11‘], ...: ‘B‘: [‘B8‘, ‘B9‘, ‘B10‘, ‘B11‘], ...: ‘C‘: [‘C8‘, ‘C9‘, ‘C10‘, ‘C11‘], ...: ‘D‘: [‘D8‘, ‘D9‘, ‘D10‘, ‘D11‘]}, ...: index=[8, 9, 10, 11]) ...: In [4]: frames = [df1, df2, df3]In [5]: result = pd.concat(frames)
Like its sibling function on ndarrays, numpy.concatenate
, pandas.concat
takes a list or dict of homogeneously-typed objects and concatenates them with some configurable handling of “what to do with the other axes”:
pd.concat(objs, axis=0, join=‘outer‘, join_axes=None, ignore_index=False, keys=None, levels=None, names=None, verify_integrity=False, copy=True)
objs
: a sequence or mapping of Series, DataFrame, or Panel objects. If a dict is passed, the sorted keys will be used as the keys argument, unless it is passed, in which case the values will be selected (see below). Any None objects will be dropped silently unless they are all None in which case a ValueError will be raised.axis
: {0, 1, ...}, default 0. The axis to concatenate along.join
: {‘inner’, ‘outer’}, default ‘outer’. How to handle indexes on other axis(es). Outer for union and inner for intersection.ignore_index
: boolean, default False. If True, do not use the index values on the concatenation axis. The resulting axis will be labeled 0, ..., n - 1. This is useful if you are concatenating objects where the concatenation axis does not have meaningful indexing information. Note the index values on the other axes are still respected in the join.join_axes
: list of Index objects. Specific indexes to use for the other n - 1 axes instead of performing inner/outer set logic.keys
: sequence, default None. Construct hierarchical index using the passed keys as the outermost level. If multiple levels passed, should contain tuples.levels
: list of sequences, default None. Specific levels (unique values) to use for constructing a MultiIndex. Otherwise they will be inferred from the keys.names
: list, default None. Names for the levels in the resulting hierarchical index.verify_integrity
: boolean, default False. Check whether the new concatenated axis contains duplicates. This can be very expensive relative to the actual data concatenation.copy
: boolean, default True. If False, do not copy data unnecessarily.
Without a little bit of context and example many of these arguments don’t make much sense. Let’s take the above example. Suppose we wanted to associate specific keys with each of the pieces of the chopped up DataFrame. We can do this using the keys
argument:
In [6]: result = pd.concat(frames, keys=[‘x‘, ‘y‘, ‘z‘])
As you can see (if you’ve read the rest of the documentation), the resulting object’s index has a hierarchical index. This means that we can now do stuff like select out each chunk by key:
In [7]: result.ix[‘y‘]Out[7]: A B C D4 A4 B4 C4 D45 A5 B5 C5 D56 A6 B6 C6 D67 A7 B7 C7 D7
It’s not a stretch to see how this can be very useful. More detail on this functionality below.
Note
It is worth noting however, that concat
(and therefore append
) makes a full copy of the data, and that constantly reusing this function can create a significant performance hit. If you need to use the operation over several datasets, use a list comprehension.
frames = [ process_your_file(f) for f in files ]result = pd.concat(frames)
Set logic on the other axes
When gluing together multiple DataFrames (or Panels or...), for example, you have a choice of how to handle the other axes (other than the one being concatenated). This can be done in three ways:
- Take the (sorted) union of them all,
join=‘outer‘
. This is the default option as it results in zero information loss. - Take the intersection,
join=‘inner‘
. - Use a specific index (in the case of DataFrame) or indexes (in the case of Panel or future higher dimensional objects), i.e. the
join_axes
argument
Here is a example of each of these methods. First, the default join=‘outer‘
behavior:
In [8]: df4 = pd.DataFrame({‘B‘: [‘B2‘, ‘B3‘, ‘B6‘, ‘B7‘], ...: ‘D‘: [‘D2‘, ‘D3‘, ‘D6‘, ‘D7‘], ...: ‘F‘: [‘F2‘, ‘F3‘, ‘F6‘, ‘F7‘]}, ...: index=[2, 3, 6, 7]) ...: In [9]: result = pd.concat([df1, df4], axis=1)
Note that the row indexes have been unioned and sorted. Here is the same thing with join=‘inner‘
:
In [10]: result = pd.concat([df1, df4], axis=1, join=‘inner‘)
Lastly, suppose we just wanted to reuse the exact index from the original DataFrame:
In [11]: result = pd.concat([df1, df4], axis=1, join_axes=[df1.index])
Concatenating using append
A useful shortcut to concat
are the append
instance methods on Series and DataFrame. These methods actually predated concat
. They concatenate along axis=0
, namely the index:
In [12]: result = df1.append(df2)
In the case of DataFrame, the indexes must be disjoint but the columns do not need to be:
In [13]: result = df1.append(df4)
append
may take multiple objects to concatenate:
In [14]: result = df1.append([df2, df3])
Note
Unlike list.append method, which appends to the original list and returns nothing,append
here does not modify df1
and returns its copy with df2
appended.
Ignoring indexes on the concatenation axis
For DataFrames which don’t have a meaningful index, you may wish to append them and ignore the fact that they may have overlapping indexes:
To do this, use the ignore_index
argument:
In [15]: result = pd.concat([df1, df4], ignore_index=True)
This is also a valid argument to DataFrame.append
:
In [16]: result = df1.append(df4, ignore_index=True)
Concatenating with mixed ndims
You can concatenate a mix of Series and DataFrames. The Series will be transformed to DataFrames with the column name as the name of the Series.
In [17]: s1 = pd.Series([‘X0‘, ‘X1‘, ‘X2‘, ‘X3‘], name=‘X‘)In [18]: result = pd.concat([df1, s1], axis=1)
If unnamed Series are passed they will be numbered consecutively.
In [19]: s2 = pd.Series([‘_0‘, ‘_1‘, ‘_2‘, ‘_3‘])In [20]: result = pd.concat([df1, s2, s2, s2], axis=1)
Passing ignore_index=True
will drop all name references.
In [21]: result = pd.concat([df1, s1], axis=1, ignore_index=True)
More concatenating with group keys
A fairly common use of the keys
argument is to override the column names when creating a new DataFrame based on existing Series. Notice how the default behaviour consists on letting the resulting DataFrame inherits the parent Series’ name, when these existed.
In [22]: s3 = pd.Series([0, 1, 2, 3], name=‘foo‘)In [23]: s4 = pd.Series([0, 1, 2, 3])In [24]: s5 = pd.Series([0, 1, 4, 5])In [25]: pd.concat([s3, s4, s5], axis=1)Out[25]: foo 0 10 0 0 01 1 1 12 2 2 43 3 3 5
Through the keys
argument we can override the existing column names.
In [26]: pd.concat([s3, s4, s5], axis=1, keys=[‘red‘,‘blue‘,‘yellow‘])Out[26]: red blue yellow0 0 0 01 1 1 12 2 2 43 3 3 5
Let’s consider now a variation on the very first example presented:
In [27]: result = pd.concat(frames, keys=[‘x‘, ‘y‘, ‘z‘])
You can also pass a dict to concat
in which case the dict keys will be used for the keys
argument (unless other keys are specified):
In [28]: pieces = {‘x‘: df1, ‘y‘: df2, ‘z‘: df3}In [29]: result = pd.concat(pieces)
In [30]: result = pd.concat(pieces, keys=[‘z‘, ‘y‘])
The MultiIndex created has levels that are constructed from the passed keys and the index of the DataFrame pieces:
In [31]: result.index.levelsOut[31]: FrozenList([[u‘z‘, u‘y‘], [4, 5, 6, 7, 8, 9, 10, 11]])
If you wish to specify other levels (as will occasionally be the case), you can do so using the levels
argument:
In [32]: result = pd.concat(pieces, keys=[‘x‘, ‘y‘, ‘z‘], ....: levels=[[‘z‘, ‘y‘, ‘x‘, ‘w‘]], ....: names=[‘group_key‘]) ....:
In [33]: result.index.levelsOut[33]: FrozenList([[u‘z‘, u‘y‘, u‘x‘, u‘w‘], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]])
Yes, this is fairly esoteric, but is actually necessary for implementing things like GroupBy where the order of a categorical variable is meaningful.
Appending rows to a DataFrame
While not especially efficient (since a new object must be created), you can append a single row to a DataFrame by passing a Series or dict to append
, which returns a new DataFrame as above.
In [34]: s2 = pd.Series([‘X0‘, ‘X1‘, ‘X2‘, ‘X3‘], index=[‘A‘, ‘B‘, ‘C‘, ‘D‘])In [35]: result = df1.append(s2, ignore_index=True)
You should use ignore_index
with this method to instruct DataFrame to discard its index. If you wish to preserve the index, you should construct an appropriately-indexed DataFrame and append or concatenate those objects.
You can also pass a list of dicts or Series:
In [36]: dicts = [{‘A‘: 1, ‘B‘: 2, ‘C‘: 3, ‘X‘: 4}, ....: {‘A‘: 5, ‘B‘: 6, ‘C‘: 7, ‘Y‘: 8}] ....: In [37]: result = df1.append(dicts, ignore_index=True)
Database-style DataFrame joining/merging
pandas has full-featured, high performance in-memory join operations idiomatically very similar to relational databases like SQL. These methods perform significantly better (in some cases well over an order of magnitude better) than other open source implementations (like base::merge.data.frame
in R). The reason for this is careful algorithmic design and internal layout of the data in DataFrame.
See the cookbook for some advanced strategies.
Users who are familiar with SQL but new to pandas might be interested in a comparison with SQL.
pandas provides a single function, merge
, as the entry point for all standard database join operations between DataFrame objects:
pd.merge(left, right, how=‘inner‘, on=None, left_on=None, right_on=None, left_index=False, right_index=False, sort=True, suffixes=(‘_x‘, ‘_y‘), copy=True, indicator=False)
left
: A DataFrame objectright
: Another DataFrame objecton
: Columns (names) to join on. Must be found in both the left and right DataFrame objects. If not passed andleft_index
andright_index
areFalse
, the intersection of the columns in the DataFrames will be inferred to be the join keysleft_on
: Columns from the left DataFrame to use as keys. Can either be column names or arrays with length equal to the length of the DataFrameright_on
: Columns from the right DataFrame to use as keys. Can either be column names or arrays with length equal to the length of the DataFrameleft_index
: IfTrue
, use the index (row labels) from the left DataFrame as its join key(s). In the case of a DataFrame with a MultiIndex (hierarchical), the number of levels must match the number of join keys from the right DataFrameright_index
: Same usage asleft_index
for the right DataFramehow
: One of‘left‘
,‘right‘
,‘outer‘
,‘inner‘
. Defaults toinner
. See below for more detailed description of each methodsort
: Sort the result DataFrame by the join keys in lexicographical order. Defaults toTrue
, setting toFalse
will improve performance substantially in many casessuffixes
: A tuple of string suffixes to apply to overlapping columns. Defaults to(‘_x‘, ‘_y‘)
.copy
: Always copy data (defaultTrue
) from the passed DataFrame objects, even when reindexing is not necessary. Cannot be avoided in many cases but may improve performance / memory usage. The cases where copying can be avoided are somewhat pathological but this option is provided nonetheless.indicator
: Add a column to the output DataFrame called_merge
with information on the source of each row._merge
is Categorical-type and takes on a value ofleft_only
for observations whose merge key only appears in‘left‘
DataFrame,right_only
for observations whose merge key only appears in‘right‘
DataFrame, andboth
if the observation’s merge key is found in both.New in version 0.17.0.
The return type will be the same as left
. If left
is a DataFrame
and right
is a subclass of DataFrame, the return type will still be DataFrame
.
merge
is a function in the pandas namespace, and it is also available as a DataFrame instance method, with the calling DataFrame being implicitly considered the left object in the join.
The related DataFrame.join
method, uses merge
internally for the index-on-index (by default) and column(s)-on-index join. If you are joining on index only, you may wish to use DataFrame.join
to save yourself some typing.
Brief primer on merge methods (relational algebra)
Experienced users of relational databases like SQL will be familiar with the terminology used to describe join operations between two SQL-table like structures (DataFrame objects). There are several cases to consider which are very important to understand:
- one-to-one joins: for example when joining two DataFrame objects on their indexes (which must contain unique values)
- many-to-one joins: for example when joining an index (unique) to one or more columns in a DataFrame
- many-to-many joins: joining columns on columns.
Note
When joining columns on columns (potentially a many-to-many join), any indexes on the passed DataFrame objects will be discarded.
It is worth spending some time understanding the result of the many-to-many join case. In SQL / standard relational algebra, if a key combination appears more than once in both tables, the resulting table will have the Cartesian product of the associated data. Here is a very basic example with one unique key combination:
In [38]: left = pd.DataFrame({‘key‘: [‘K0‘, ‘K1‘, ‘K2‘, ‘K3‘], ....: ‘A‘: [‘A0‘, ‘A1‘, ‘A2‘, ‘A3‘], ....: ‘B‘: [‘B0‘, ‘B1‘, ‘B2‘, ‘B3‘]}) ....: In [39]: right = pd.DataFrame({‘key‘: [‘K0‘, ‘K1‘, ‘K2‘, ‘K3‘], ....: ‘C‘: [‘C0‘, ‘C1‘, ‘C2‘, ‘C3‘], ....: ‘D‘: [‘D0‘, ‘D1‘, ‘D2‘, ‘D3‘]}) ....: In [40]: result = pd.merge(left, right, on=‘key‘)
Here is a more complicated example with multiple join keys:
In [41]: left = pd.DataFrame({‘key1‘: [‘K0‘, ‘K0‘, ‘K1‘, ‘K2‘], ....: ‘key2‘: [‘K0‘, ‘K1‘, ‘K0‘, ‘K1‘], ....: ‘A‘: [‘A0‘, ‘A1‘, ‘A2‘, ‘A3‘], ....: ‘B‘: [‘B0‘, ‘B1‘, ‘B2‘, ‘B3‘]}) ....: In [42]: right = pd.DataFrame({‘key1‘: [‘K0‘, ‘K1‘, ‘K1‘, ‘K2‘], ....: ‘key2‘: [‘K0‘, ‘K0‘, ‘K0‘, ‘K0‘], ....: ‘C‘: [‘C0‘, ‘C1‘, ‘C2‘, ‘C3‘], ....: ‘D‘: [‘D0‘, ‘D1‘, ‘D2‘, ‘D3‘]}) ....: In [43]: result = pd.merge(left, right, on=[‘key1‘, ‘key2‘])
The how
argument to merge
specifies how to determine which keys are to be included in the resulting table. If a key combination does not appear in either the left or right tables, the values in the joined table will be NA
. Here is a summary of the how
options and their SQL equivalent names:
Merge method | SQL Join Name | Description |
---|---|---|
left | LEFT OUTER JOIN | Use keys from left frame only |
right | RIGHT OUTER JOIN | Use keys from right frame only |
outer | FULL OUTER JOIN | Use union of keys from both frames |
inner | INNER JOIN | Use intersection of keys from both frames |
In [44]: result = pd.merge(left, right, how=‘left‘, on=[‘key1‘, ‘key2‘])
In [45]: result = pd.merge(left, right, how=‘right‘, on=[‘key1‘, ‘key2‘])
In [46]: result = pd.merge(left, right, how=‘outer‘, on=[‘key1‘, ‘key2‘])
In [47]: result = pd.merge(left, right, how=‘inner‘, on=[‘key1‘, ‘key2‘])
The merge indicator
New in version 0.17.0.
merge
now accepts the argument indicator
. If True
, a Categorical-type column called _merge
will be added to the output object that takes on values:
Observation Origin _merge
valueMerge key only in ‘left‘
frameleft_only
Merge key only in ‘right‘
frameright_only
Merge key in both frames both
In [48]: df1 = pd.DataFrame({‘col1‘: [0, 1], ‘col_left‘:[‘a‘, ‘b‘]})In [49]: df2 = pd.DataFrame({‘col1‘: [1, 2, 2],‘col_right‘:[2, 2, 2]})In [50]: pd.merge(df1, df2, on=‘col1‘, how=‘outer‘, indicator=True)Out[50]: col1 col_left col_right _merge0 0 a NaN left_only1 1 b 2.0 both2 2 NaN 2.0 right_only3 2 NaN 2.0 right_only
The indicator
argument will also accept string arguments, in which case the indicator function will use the value of the passed string as the name for the indicator column.
In [51]: pd.merge(df1, df2, on=‘col1‘, how=‘outer‘, indicator=‘indicator_column‘)Out[51]: col1 col_left col_right indicator_column0 0 a NaN left_only1 1 b 2.0 both2 2 NaN 2.0 right_only3 2 NaN 2.0 right_only
Joining on index
DataFrame.join
is a convenient method for combining the columns of two potentially differently-indexed DataFrames into a single result DataFrame. Here is a very basic example:
In [52]: left = pd.DataFrame({‘A‘: [‘A0‘, ‘A1‘, ‘A2‘], ....: ‘B‘: [‘B0‘, ‘B1‘, ‘B2‘]}, ....: index=[‘K0‘, ‘K1‘, ‘K2‘]) ....: In [53]: right = pd.DataFrame({‘C‘: [‘C0‘, ‘C2‘, ‘C3‘], ....: ‘D‘: [‘D0‘, ‘D2‘, ‘D3‘]}, ....: index=[‘K0‘, ‘K2‘, ‘K3‘]) ....: In [54]: result = left.join(right)
In [55]: result = left.join(right, how=‘outer‘)
In [56]: result = left.join(right, how=‘inner‘)
The data alignment here is on the indexes (row labels). This same behavior can be achieved using merge
plus additional arguments instructing it to use the indexes:
In [57]: result = pd.merge(left, right, left_index=True, right_index=True, how=‘outer‘)
In [58]: result = pd.merge(left, right, left_index=True, right_index=True, how=‘inner‘);
Joining key columns on an index
join
takes an optional on
argument which may be a column or multiple column names, which specifies that the passed DataFrame is to be aligned on that column in the DataFrame. These two function calls are completely equivalent:
left.join(right, on=key_or_keys)pd.merge(left, right, left_on=key_or_keys, right_index=True, how=‘left‘, sort=False)
Obviously you can choose whichever form you find more convenient. For many-to-one joins (where one of the DataFrame’s is already indexed by the join key), using join
may be more convenient. Here is a simple example:
In [59]: left = pd.DataFrame({‘A‘: [‘A0‘, ‘A1‘, ‘A2‘, ‘A3‘], ....: ‘B‘: [‘B0‘, ‘B1‘, ‘B2‘, ‘B3‘], ....: ‘key‘: [‘K0‘, ‘K1‘, ‘K0‘, ‘K1‘]}) ....: In [60]: right = pd.DataFrame({‘C‘: [‘C0‘, ‘C1‘], ....: ‘D‘: [‘D0‘, ‘D1‘]}, ....: index=[‘K0‘, ‘K1‘]) ....: In [61]: result = left.join(right, on=‘key‘)
In [62]: result = pd.merge(left, right, left_on=‘key‘, right_index=True, ....: how=‘left‘, sort=False); ....:
To join on multiple keys, the passed DataFrame must have a MultiIndex
:
In [63]: left = pd.DataFrame({‘A‘: [‘A0‘, ‘A1‘, ‘A2‘, ‘A3‘], ....: ‘B‘: [‘B0‘, ‘B1‘, ‘B2‘, ‘B3‘], ....: ‘key1‘: [‘K0‘, ‘K0‘, ‘K1‘, ‘K2‘], ....: ‘key2‘: [‘K0‘, ‘K1‘, ‘K0‘, ‘K1‘]}) ....: In [64]: index = pd.MultiIndex.from_tuples([(‘K0‘, ‘K0‘), (‘K1‘, ‘K0‘), ....: (‘K2‘, ‘K0‘), (‘K2‘, ‘K1‘)]) ....: In [65]: right = pd.DataFrame({‘C‘: [‘C0‘, ‘C1‘, ‘C2‘, ‘C3‘], ....: ‘D‘: [‘D0‘, ‘D1‘, ‘D2‘, ‘D3‘]}, ....: index=index) ....:
Now this can be joined by passing the two key column names:
In [66]: result = left.join(right, on=[‘key1‘, ‘key2‘])
The default for DataFrame.join
is to perform a left join (essentially a “VLOOKUP” operation, for Excel users), which uses only the keys found in the calling DataFrame. Other join types, for example inner join, can be just as easily performed:
In [67]: result = left.join(right, on=[‘key1‘, ‘key2‘], how=‘inner‘)
As you can see, this drops any rows where there was no match.
Joining a single Index to a Multi-index
New in version 0.14.0.
You can join a singly-indexed DataFrame
with a level of a multi-indexed DataFrame
. The level will match on the name of the index of the singly-indexed frame against a level name of the multi-indexed frame.
In [68]: left = pd.DataFrame({‘A‘: [‘A0‘, ‘A1‘, ‘A2‘], ....: ‘B‘: [‘B0‘, ‘B1‘, ‘B2‘]}, ....: index=pd.Index([‘K0‘, ‘K1‘, ‘K2‘], name=‘key‘)) ....: In [69]: index = pd.MultiIndex.from_tuples([(‘K0‘, ‘Y0‘), (‘K1‘, ‘Y1‘), ....: (‘K2‘, ‘Y2‘), (‘K2‘, ‘Y3‘)], ....: names=[‘key‘, ‘Y‘]) ....: In [70]: right = pd.DataFrame({‘C‘: [‘C0‘, ‘C1‘, ‘C2‘, ‘C3‘], ....: ‘D‘: [‘D0‘, ‘D1‘, ‘D2‘, ‘D3‘]}, ....: index=index) ....: In [71]: result = left.join(right, how=‘inner‘)
This is equivalent but less verbose and more memory efficient / faster than this.
In [72]: result = pd.merge(left.reset_index(), right.reset_index(), ....: on=[‘key‘], how=‘inner‘).set_index([‘key‘,‘Y‘]) ....:
Joining with two multi-indexes
This is not Implemented via join
at-the-moment, however it can be done using the following.
In [73]: index = pd.MultiIndex.from_tuples([(‘K0‘, ‘X0‘), (‘K0‘, ‘X1‘), ....: (‘K1‘, ‘X2‘)], ....: names=[‘key‘, ‘X‘]) ....: In [74]: left = pd.DataFrame({‘A‘: [‘A0‘, ‘A1‘, ‘A2‘], ....: ‘B‘: [‘B0‘, ‘B1‘, ‘B2‘]}, ....: index=index) ....: In [75]: result = pd.merge(left.reset_index(), right.reset_index(), ....: on=[‘key‘], how=‘inner‘).set_index([‘key‘,‘X‘,‘Y‘]) ....:
Overlapping value columns
The merge suffixes
argument takes a tuple of list of strings to append to overlapping column names in the input DataFrames to disambiguate the result columns:
In [76]: left = pd.DataFrame({‘k‘: [‘K0‘, ‘K1‘, ‘K2‘], ‘v‘: [1, 2, 3]})In [77]: right = pd.DataFrame({‘k‘: [‘K0‘, ‘K0‘, ‘K3‘], ‘v‘: [4, 5, 6]})In [78]: result = pd.merge(left, right, on=‘k‘)
In [79]: result = pd.merge(left, right, on=‘k‘, suffixes=[‘_l‘, ‘_r‘])
DataFrame.join
has lsuffix
and rsuffix
arguments which behave similarly.
In [80]: left = left.set_index(‘k‘)In [81]: right = right.set_index(‘k‘)In [82]: result = left.join(right, lsuffix=‘_l‘, rsuffix=‘_r‘)
Joining multiple DataFrame or Panel objects
A list or tuple of DataFrames can also be passed to DataFrame.join
to join them together on their indexes. The same is true for Panel.join
.
In [83]: right2 = pd.DataFrame({‘v‘: [7, 8, 9]}, index=[‘K1‘, ‘K1‘, ‘K2‘])In [84]: result = left.join([right, right2])
Merging together values within Series or DataFrame columns
Another fairly common situation is to have two like-indexed (or similarly indexed) Series or DataFrame objects and wanting to “patch” values in one object from values for matching indices in the other. Here is an example:
In [85]: df1 = pd.DataFrame([[np.nan, 3., 5.], [-4.6, np.nan, np.nan], ....: [np.nan, 7., np.nan]]) ....: In [86]: df2 = pd.DataFrame([[-42.6, np.nan, -8.2], [-5., 1.6, 4]], ....: index=[1, 2]) ....:
For this, use the combine_first
method:
In [87]: result = df1.combine_first(df2)
Note that this method only takes values from the right DataFrame if they are missing in the left DataFrame. A related method, update
, alters non-NA values inplace:
In [88]: df1.update(df2)
Timeseries friendly merging
Merging Ordered Data
A merge_ordered()
function allows combining time series and other ordered data. In particular it has an optional fill_method
keyword to fill/interpolate missing data:
In [89]: left = pd.DataFrame({‘k‘: [‘K0‘, ‘K1‘, ‘K1‘, ‘K2‘], ....: ‘lv‘: [1, 2, 3, 4], ....: ‘s‘: [‘a‘, ‘b‘, ‘c‘, ‘d‘]}) ....: In [90]: right = pd.DataFrame({‘k‘: [‘K1‘, ‘K2‘, ‘K4‘], ....: ‘rv‘: [1, 2, 3]}) ....: In [91]: pd.merge_ordered(left, right, fill_method=‘ffill‘, left_by=‘s‘)Out[91]: k lv s rv0 K0 1.0 a NaN1 K1 1.0 a 1.02 K2 1.0 a 2.03 K4 1.0 a 3.04 K1 2.0 b 1.05 K2 2.0 b 2.06 K4 2.0 b 3.07 K1 3.0 c 1.08 K2 3.0 c 2.09 K4 3.0 c 3.010 K1 NaN d 1.011 K2 4.0 d 2.012 K4 4.0 d 3.0
Merging AsOf
New in version 0.19.0.
A merge_asof()
is similar to an ordered left-join except that we match on nearest key rather than equal keys. For each row in the left
DataFrame, we select the last row in the right
DataFrame whose on
key is less than the left’s key. Both DataFrames must be sorted by the key.
Optionally an asof merge can perform a group-wise merge. This matches the by
key equally, in addition to the nearest match on the on
key.
For example; we might have trades
and quotes
and we want to asof
merge them.
In [92]: trades = pd.DataFrame({ ....: ‘time‘: pd.to_datetime([‘20160525 13:30:00.023‘, ....: ‘20160525 13:30:00.038‘, ....: ‘20160525 13:30:00.048‘, ....: ‘20160525 13:30:00.048‘, ....: ‘20160525 13:30:00.048‘]), ....: ‘ticker‘: [‘MSFT‘, ‘MSFT‘, ....: ‘GOOG‘, ‘GOOG‘, ‘AAPL‘], ....: ‘price‘: [51.95, 51.95, ....: 720.77, 720.92, 98.00], ....: ‘quantity‘: [75, 155, ....: 100, 100, 100]}, ....: columns=[‘time‘, ‘ticker‘, ‘price‘, ‘quantity‘]) ....: In [93]: quotes = pd.DataFrame({ ....: ‘time‘: pd.to_datetime([‘20160525 13:30:00.023‘, ....: ‘20160525 13:30:00.023‘, ....: ‘20160525 13:30:00.030‘, ....: ‘20160525 13:30:00.041‘, ....: ‘20160525 13:30:00.048‘, ....: ‘20160525 13:30:00.049‘, ....: ‘20160525 13:30:00.072‘, ....: ‘20160525 13:30:00.075‘]), ....: ‘ticker‘: [‘GOOG‘, ‘MSFT‘, ‘MSFT‘, ....: ‘MSFT‘, ‘GOOG‘, ‘AAPL‘, ‘GOOG‘, ....: ‘MSFT‘], ....: ‘bid‘: [720.50, 51.95, 51.97, 51.99, ....: 720.50, 97.99, 720.50, 52.01], ....: ‘ask‘: [720.93, 51.96, 51.98, 52.00, ....: 720.93, 98.01, 720.88, 52.03]}, ....: columns=[‘time‘, ‘ticker‘, ‘bid‘, ‘ask‘]) ....:
In [94]: tradesOut[94]: time ticker price quantity0 2016-05-25 13:30:00.023 MSFT 51.95 751 2016-05-25 13:30:00.038 MSFT 51.95 1552 2016-05-25 13:30:00.048 GOOG 720.77 1003 2016-05-25 13:30:00.048 GOOG 720.92 1004 2016-05-25 13:30:00.048 AAPL 98.00 100In [95]: quotesOut[95]: time ticker bid ask0 2016-05-25 13:30:00.023 GOOG 720.50 720.931 2016-05-25 13:30:00.023 MSFT 51.95 51.962 2016-05-25 13:30:00.030 MSFT 51.97 51.983 2016-05-25 13:30:00.041 MSFT 51.99 52.004 2016-05-25 13:30:00.048 GOOG 720.50 720.935 2016-05-25 13:30:00.049 AAPL 97.99 98.016 2016-05-25 13:30:00.072 GOOG 720.50 720.887 2016-05-25 13:30:00.075 MSFT 52.01 52.03
By default we are taking the asof of the quotes.
In [96]: pd.merge_asof(trades, quotes, ....: on=‘time‘, ....: by=‘ticker‘) ....: Out[96]: time ticker price quantity bid ask0 2016-05-25 13:30:00.023 MSFT 51.95 75 51.95 51.961 2016-05-25 13:30:00.038 MSFT 51.95 155 51.97 51.982 2016-05-25 13:30:00.048 GOOG 720.77 100 720.50 720.933 2016-05-25 13:30:00.048 GOOG 720.92 100 720.50 720.934 2016-05-25 13:30:00.048 AAPL 98.00 100 NaN NaN
We only asof within 2ms
betwen the quote time and the trade time.
In [97]: pd.merge_asof(trades, quotes, ....: on=‘time‘, ....: by=‘ticker‘, ....: tolerance=pd.Timedelta(‘2ms‘)) ....: Out[97]: time ticker price quantity bid ask0 2016-05-25 13:30:00.023 MSFT 51.95 75 51.95 51.961 2016-05-25 13:30:00.038 MSFT 51.95 155 NaN NaN2 2016-05-25 13:30:00.048 GOOG 720.77 100 720.50 720.933 2016-05-25 13:30:00.048 GOOG 720.92 100 720.50 720.934 2016-05-25 13:30:00.048 AAPL 98.00 100 NaN NaN
We only asof within 10ms
betwen the quote time and the trade time and we exclude exact matches on time. Note that though we exclude the exact matches (of the quotes), prior quotes DO propogate to that point in time.
In [98]: pd.merge_asof(trades, quotes, ....: on=‘time‘, ....: by=‘ticker‘, ....: tolerance=pd.Timedelta(‘10ms‘), ....: allow_exact_matches=False) ....: Out[98]: time ticker price quantity bid ask0 2016-05-25 13:30:00.023 MSFT 51.95 75 NaN NaN1 2016-05-25 13:30:00.038 MSFT 51.95 155 51.97 51.982 2016-05-25 13:30:00.048 GOOG 720.77 100 NaN NaN3 2016-05-25 13:30:00.048 GOOG 720.92 100 NaN NaN4 2016-05-25 13:30:00.048 AAPL 98.00 100 NaN NaN
Pandas -- Merge,join and concatenate