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Leetcode: Spiral Matrix II
Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order.For example,Given n = 3,You should return the following matrix:[ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7, 6, 5 ]]
跟Spiral Matrix一样的处理,甚至还简单一些,这个确定是方阵。分层,然后按照上右下左的顺序放入数组中。每个元素只访问一次,时间复杂度是O(n^2)。
1 public class Solution { 2 public int[][] generateMatrix(int n) { 3 int[][] res = new int[n][n]; 4 if (n < 0) return null; 5 int levelNum = n / 2; 6 int count = 1; 7 for (int level=0; level<levelNum; level++) { 8 for (int i=level; i<n-1-level; i++) { 9 res[level][i] = count++;10 }11 for (int i=level; i<n-1-level; i++) {12 res[i][n-1-level] = count++;13 }14 for (int i=n-1-level; i>level; i--) {15 res[n-1-level][i] = count++;16 }17 for (int i=n-1-level; i>level; i--) {18 res[i][level] = count++;19 }20 }21 if (n % 2 == 1) {22 res[levelNum][levelNum] = count;23 }24 return res;25 }26 }
Leetcode: Spiral Matrix II
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