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java实现单链表

早上清早起来,第一件事就是打开博客园随便的翻看下博客, 看到有篇文章提到的算法数据结构,实现一个单链表的操作。作者是使用c#编写的, 那么我这里通过java也来弄弄。

首先定义一个Node类

public class Node {     protected Node next; //指针域       public  int data;//数据域              public Node( int data) {             this. data =http://www.mamicode.com/ data;       }              //显示此节点       public void display() {            System. out.print( data + " ");       }  }

接下来定义一个单链表,并实现相关方法:

public class LinkList {    public Node first; // 定义一个头结点    private int pos = 0;// 节点的位置    public LinkList() {        this.first = null;    }    // 插入一个头节点    public void addFirstNode(int data) {        Node node = new Node(data);        node.next = first;        first = node;    }    // 删除一个头结点,并返回头结点    public Node deleteFirstNode() {        Node tempNode = first;        first = tempNode.next;        return tempNode;    }    // 在任意位置插入节点 在index的后面插入    public void add(int index, int data) {        Node node = new Node(data);        Node current = first;        Node previous = first;        while (pos != index) {            previous = current;            current = current.next;            pos++;        }        node.next = current;        previous.next = node;        pos = 0;    }    // 删除任意位置的节点    public Node deleteByPos(int index) {        Node current = first;        Node previous = first;        while (pos != index) {            pos++;            previous = current;            current = current.next;        }        if (current == first) {            first = first.next;        } else {            pos = 0;            previous.next = current.next;        }        return current;    }    // 根据节点的data删除节点(仅仅删除第一个)    public Node deleteByData(int data) {        Node current = first;        Node previous = first; // 记住上一个节点        while (current.data != data) {            if (current.next == null) {                return null;            }            previous = current;            current = current.next;        }        if (current == first) {            first = first.next;        } else {            previous.next = current.next;        }        return current;    }    // 显示出所有的节点信息    public void displayAllNodes() {        Node current = first;        while (current != null) {            current.display();            current = current.next;        }        System.out.println();    }    // 根据位置查找节点信息    public Node findByPos(int index) {        Node current = first;        if (pos != index) {            current = current.next;            pos++;        }        return current;    }    // 根据数据查找节点信息    public Node findByData(int data) {        Node current = first;        while (current.data != data) {            if (current.next == null)                return null;            current = current.next;        }        return current;    }}

最后我们可以通过测试类来做相关测试:

public class TestLinkList {    public static void main(String[] args) {          LinkList linkList = new LinkList();          linkList.addFirstNode(20);          linkList.addFirstNode(21);          linkList.addFirstNode(19);           //print19,21,20          linkList.add(1, 22); //print19,22,21,20          linkList.add(2, 23); //print19,22,23,21,20          linkList.add(3, 99); //print19,22,23,99,21,20        //调用此方法会print 19,22,23,99,21,20         linkList.displayAllNodes();          }}

至此,对单链表的操作就笔记到这里了。

java实现单链表