首页 > 代码库 > leetcode - Rotate List
leetcode - Rotate List
Given a list, rotate the list to the right by k places, where k is non-negative.
For example:
Given 1->2->3->4->5->NULL
and k = 2
,
return 4->5->1->2->3->NULL
.
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ struct ListNode { int val; ListNode *next; ListNode(int x) : val(x), next(NULL) {} }; class Solution { public: ListNode *rotateRight(ListNode *head, int k) { if(head == NULL || head->next == NULL || k == 0) return head; ListNode *p = head,*q = NULL; int ListNodeLength = 0; while(p != NULL) { ListNodeLength++; q = p; p = p->next; } k %= ListNodeLength; p = head; for(int i = 0; i < ListNodeLength - k - 1; i++) { p = p->next; } q->next = head; head = p->next; p->next = NULL; return head; } };
leetcode - Rotate List
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。