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【leetcode?python】Convert a Number to Hexadecimal
#-*- coding: UTF-8 -*-
class Solution(object):
hexDic={0:‘0‘,1:‘1‘,2:‘2‘,3:‘3‘,4:‘4‘,5:‘5‘,6:‘6‘,7:‘7‘,8:‘8‘,9:‘9‘,\
10:‘a‘,
11:‘b‘,
12:‘c‘,
13:‘d‘,
14:‘e‘,
15:‘f‘}
def toHex(self, num):
returnStr=[]
if(num==0):
return ‘0‘
if num>=pow(2,32) or num <-pow(2,32):
return False
if(num<0):
print num
num=pow(2,32)-1-abs(num)+1
print num
while True:
remainder=num%16
divisior=num/16
returnStr.append(self.hexDic.get(remainder))
print remainder,divisior
if(divisior<16):
returnStr.append(self.hexDic.get(divisior))
break
num=divisior
print returnStr
returnStr.reverse()
if returnStr[0]==‘0‘:del returnStr[0]
return ‘‘.join(returnStr)
sol=Solution()
print sol.toHex(1)
【leetcode?python】Convert a Number to Hexadecimal