1 #include "stdafx.h"  2 #include <stdlib.h>  3 #include <string.h>  4 #include <time.h>  5   6 #define IS_LEAP_YEAR(y)  (((y) % 4 == 0 && (y) % 100 != 0) || (y) % 400 == 0)  7   8 #define if_not_eual_ret(left, right) do {  9     if (left < right) {return true;} else if(left > right) {return false;} 10     } while(0) 11  12 //从网上抄的 计算日期相差天数的函数 13 int day_diff(int year_start, int month_start, int day_start,  14     int year_end, int month_end, int day_end) 15 { 16     int y2, m2, d2; 17     int y1, m1, d1; 18  19     m1 = (month_start + 9) % 12; 20     y1 = year_start - m1/10; 21     d1 = 365*y1 + y1/4 - y1/100 + y1/400 + (m1*306 + 5)/10 + (day_start - 1); 22  23     m2 = (month_end + 9) % 12; 24     y2 = year_end - m2/10; 25     d2 = 365*y2 + y2/4 - y2/100 + y2/400 + (m2*306 + 5)/10 + (day_end - 1); 26  27     return (d2 - d1); 28 } 29  30  31 class CMyDateTime 32 { 33 public: 34     CMyDateTime(int sec_from_beg = 0) 35     { 36         m_sec_from_beg = sec_from_beg; 37     } 38  39     CMyDateTime(int year, int month, int day, int hour, int minute, int second) 40     { 41         m_sec_from_beg = to_second(year, month, day, hour, minute, second); 42     } 43  44     bool operator < (const CMyDateTime& theDate) 45     { 46         return m_sec_from_beg < theDate.m_sec_from_beg; 47     } 48  49     //获得0001 01:01:00至当前时间秒数 50     long long to_second() 51     { 52         return m_sec_from_beg; 53     } 54  55      56     //年 取1900-3000 月 取0-11 日 取1-31 时分秒 取0-59 57     static long long to_second(int year, int month, int day, int hour, int minute, int second) 58     { 59         //获取当前日期至纪元1年的天数 60         int y1 = year, m1 = 0, d1 = day - 1; 61         long long sec; 62  63         //每月天数 64         int month_day[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; 65  66         if (IS_LEAP_YEAR(year)) 67         { 68             month_day[1]++; 69         } 70         for (int i = 0; i < month; i++) 71         { 72             m1 += month_day[i]; 73         } 74  75         y1 -= 1; 76         d1 = 365*y1 + y1/4 - y1/100 + y1/400 + m1 + d1; 77  78         //24小时 60分 60秒 79         sec = (long long)d1 * (24 * 60 * 60); 80         sec += hour * 3600 + minute * 60 + second; 81         return sec; 82     } 83  84     //把秒数转换成标准日期 85     bool to_date(int& year, int& month, int& day, int& hour, int& minute, int& second) 86     { 87         // 先计算大概年份，用秒数除以366天秒数 88         int day_from_beg = (int)(m_sec_from_beg / (24 * 60 * 60)); 89  90         int second_left = int(m_sec_from_beg - day_from_beg * (long long) (24 * 60 * 60)); 91         hour = second_left / (60 * 60); 92  93         second_left = int (second_left - hour * (60 * 60)); 94         minute = second_left / 60; 95         second = second_left % 60; 96  97         int year_cnt = day_from_beg / 366; 98         //每年365天 闰年多一天 99         int day_from_beg_to_year = (year_cnt * 365 + year_cnt / 4 - year_cnt / 100 + year_cnt / 400);100 101         //然后逐年累加天数，直到天数大于day_from_beg102         while (day_from_beg_to_year <= day_from_beg)103         {104             if (IS_LEAP_YEAR(year_cnt + 1))105             {106                 day_from_beg_to_year += 366;107             }108             else109             {110                 day_from_beg_to_year += 365;111             }112             year_cnt++;113         }114         //因为是要取最后一个小于等于在数 所以在这里要减一115         year_cnt--;116 117         //知道年份后，再计算月份 先计算出当前日期距离今年开始相差多少天118         int day_from_year = day_from_beg - (year_cnt * 365 + year_cnt / 4 - year_cnt / 100 + year_cnt / 400);119         //今年的年数 = 经过的年数 + 1120         year = year_cnt + 1;121 122         //每月天数123         int month_day[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};124 125         if (IS_LEAP_YEAR(year))126         {127             month_day[1]++;128         }129 130         for (month = 0; month < 12; month++)131         {132             if ((day_from_year - month_day[month]) < 0)133             {134                 break;135             }136 137             day_from_year -= month_day[month];138         }139         day = day_from_year + 1;140         return true;141     }142 private:143     //当前日期至纪元1年的秒数144     long long m_sec_from_beg;145 };146 147 //测试函数，测试每一秒钟从人类日期格式转换成CMyDateTime 再转换回来是否正确148 void test_time()149 {150     int month_day[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};151 152     for (int year = 1; year < 2100; year++)153     {154         double start = GetTickCount();155         bool is_leap = IS_LEAP_YEAR(year);156         if (is_leap)157         {158             month_day[1] = 29;159         }160 161         for (int month = 0; month < 12; month++)162         {163             for (int day = 1; day <= month_day[month]; day++)164             {165                 for (int hour = 0; hour < 24; hour++)166                 {167                     for (int minute = 0; minute < 60; minute++)168                     {169                         for (int second = 0; second < 60; second++)170                         {171                             CMyDateTime t(year, month, day, hour, minute, second);172                             int year_new, month_new, day_new, hour_new, minute_new, second_new;173                             if (t.to_date(year_new, month_new, day_new, hour_new, minute_new, second_new))174                             {175                                 if (year != year_new || month != month_new || day_new != day ||176                                     hour != hour_new || minute != minute_new || second != second_new)177                                 {178                                     printf("day = %d day_new = %d\n", day, day_new);179                                     printf("month = %d month_new = %d\n", month, month_new);180                                     printf("year = %d year_new = %d\n", year, year_new);181 182 183                                     printf("hour = %d hour_new = %d\n", hour, hour_new);184                                     printf("minute = %d minute_new = %d\n", minute, minute_new);185                                     printf("second = %d second_new = %d\n", second, second_new);186                                     printf("------------------------\n");187                                 }188                             }189                         }190                     }191                 }192             }193         }194 195         if (is_leap)196         {197             month_day[1] = 28;198         }199 200         //我的机器一年花5秒左右 效率不是特别高 但目前没有优化头绪201         printf("总共耗时 %f 毫秒\n", GetTickCount() - start);202         printf("------------[%04d]------------\n", year);203     }204 }