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小米面试题：手机分身，电话号码隐藏。
小米面试题：
手机分身，电话号码隐藏。
0-9分别对应ZERO,ONE,TWO,...,NINE
为保证手机拨号安全性，拨号后，存为对应的字符串，并打乱顺序，保证安全性。
现在给定一个字符串，求最小的数字组合
例：
TWOONE
OTNWOE
12
12
分析：
| 关键字搜索： | 第一次 | 第二次 | 第三次 |
| 0 ZERO | Z | ||
| 1 ONE | O | ||
| 2 TWO | W | ||
| 3 THREE | R | ||
| 4 FOUR | U | ||
| 5 FIVE | F | ||
| 6 SIX | X | ||
| 7 SENVE | S | ||
| 8 EIGHT | G | ||
| 9 NINE | I/E |
代码实现如下：
1 #include "stdafx.h" 2 #include<string> 3 #include<iostream> 4 using namespace std; 5 6 int main() 7 { 8 int zidian[26],number[10]; 9 memset(zidian,0,26*sizeof(int)); 10 memset(number,0,10*sizeof(int)); 11 string numberString; 12 while(cin >> numberString) 13 {//while循环，无限获取测试用例 14 for (int i = 0; i < numberString.size(); i++) 15 {//for循环建立字典索引，直接针对字典查，而不再单个搜索。 16 char tempChar = numberString[i]; 17 zidian[(int)tempChar - 65] += 1; 18 } 19 int tempNum; 20 //查找0 ZERO Z 21 if(zidian[(int)‘Z‘ - 65] != 0) 22 { 23 tempNum = zidian[(int)‘Z‘ - 65]; 24 zidian[(int)‘Z‘ - 65] = 0; 25 zidian[(int)‘E‘ - 65] -= tempNum; 26 zidian[(int)‘R‘ - 65] -= tempNum; 27 zidian[(int)‘O‘ - 65] -= tempNum; 28 number[0] = tempNum; 29 } 30 //查找2 TWO W 31 if(zidian[(int)‘W‘ - 65] != 0) 32 { 33 tempNum = zidian[(int)‘W‘ - 65]; 34 zidian[(int)‘W‘ - 65] = 0; 35 zidian[(int)‘T‘ - 65] -= tempNum; 36 zidian[(int)‘O‘ - 65] -= tempNum; 37 number[2] = tempNum; 38 } 39 //查找4 FOUR U 40 if(zidian[(int)‘U‘ - 65] != 0) 41 { 42 tempNum = zidian[(int)‘U‘ - 65]; 43 zidian[(int)‘U‘ - 65] = 0; 44 zidian[(int)‘F‘ - 65] -= tempNum; 45 zidian[(int)‘R‘ - 65] -= tempNum; 46 zidian[(int)‘O‘ - 65] -= tempNum; 47 number[4] = tempNum; 48 } 49 //查找6 SIX X 50 if(zidian[(int)‘X‘ - 65] != 0) 51 { 52 tempNum = zidian[(int)‘X‘ - 65]; 53 zidian[(int)‘X‘ - 65] = 0; 54 zidian[(int)‘S‘ - 65] -= tempNum; 55 zidian[(int)‘I‘ - 65] -= tempNum; 56 number[6] = tempNum; 57 } 58 //查找8 EIGHT G 59 if(zidian[(int)‘G‘ - 65] != 0) 60 { 61 tempNum = zidian[(int)‘G‘ - 65]; 62 zidian[(int)‘G‘ - 65] = 0; 63 zidian[(int)‘E‘ - 65] -= tempNum; 64 zidian[(int)‘I‘ - 65] -= tempNum; 65 zidian[(int)‘H‘ - 65] -= tempNum; 66 zidian[(int)‘T‘ - 65] -= tempNum; 67 number[8] = tempNum; 68 } 69 //查找1 ONE O 70 if(zidian[(int)‘O‘ - 65] != 0) 71 { 72 tempNum = zidian[(int)‘O‘ - 65]; 73 zidian[(int)‘O‘ - 65] = 0; 74 zidian[(int)‘N‘ - 65] -= tempNum; 75 zidian[(int)‘E‘ - 65] -= tempNum; 76 number[1] = tempNum; 77 } 78 //查找3 THREE R 79 if(zidian[(int)‘R‘ - 65] != 0) 80 { 81 tempNum = zidian[(int)‘R‘ - 65]; 82 zidian[(int)‘R‘ - 65] = 0; 83 zidian[(int)‘T‘ - 65] -= tempNum; 84 zidian[(int)‘H‘ - 65] -= tempNum; 85 zidian[(int)‘E‘ - 65] -= 2 * tempNum; 86 number[3] = tempNum; 87 } 88 //查找5 FIVE F 89 if(zidian[(int)‘F‘ - 65] != 0) 90 { 91 tempNum = zidian[(int)‘F‘ - 65]; 92 zidian[(int)‘F‘ - 65] = 0; 93 zidian[(int)‘I‘ - 65] -= tempNum; 94 zidian[(int)‘V‘ - 65] -= tempNum; 95 zidian[(int)‘E‘ - 65] -= tempNum; 96 number[5] = tempNum; 97 } 98 //查找7 SEVEN S 99 if(zidian[(int)‘S‘ - 65] != 0)100 {101 tempNum = zidian[(int)‘S‘ - 65];102 zidian[(int)‘S‘ - 65] = 0;103 zidian[(int)‘E‘ - 65] -= 2 * tempNum;104 zidian[(int)‘V‘ - 65] -= tempNum;105 zidian[(int)‘N‘ - 65] -= tempNum;106 number[4] = tempNum;107 }108 //查找9 NINE I109 if(zidian[(int)‘I‘ - 65] != 0)110 {111 tempNum = zidian[(int)‘I‘ - 65];112 zidian[(int)‘I‘ - 65] = 0;113 zidian[(int)‘N‘ - 65] -= 2 * tempNum;114 zidian[(int)‘E‘ - 65] -= tempNum;115 number[4] = tempNum;116 }117 //转化为字符串输出（保证最小）118 string sum;119 for (int i = 0; i < 10; i++)120 {121 string temps(number[i],(char)(i+48));122 sum += temps;123 }124 cout << sum << endl;125 }126 return 0;127 }
小米面试题：手机分身，电话号码隐藏。
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