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C语言下的简易计算器

 1 #include <stdio.h> 2 #include <math.h> 3 int main() 4 {     5     double data1, data2; 6     char op; 7     while (3 == scanf("%lf%c%lf", &data1, &op, &data2) ) 8         {  9             double result;10             printf("%lf%c%lf=", data1,data2);11             switch (op)12             {13                 case +:14                 result = data1 + data2;15                 break;16                 case -:17                 result = data1 - data2;18                 break;    19                 case *:20                 result = data1 * data2;21                 break;    22                 case /:          23                 result = data1 / data2;24                 break;      25                 default:;26             }        27             printf("%lf\n", result);    28         }    29 30     return 0;31 }