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9.29 奶牛练习题
/*bzoj 1613*//*暴力5884ms*/#include<cstdio>#define maxn 10010using namespace std;int n,m,a[maxn],f[maxn][510];int max(int x,int y){ return x>y?x:y;}int main(){ scanf("%d%d",&n,&m); for(int i=1;i<=n;i++) scanf("%d",&a[i]); for(int i=1;i<=n;i++) for(int j=0;j<=m;j++){ if(j>0)f[i][j]=max(f[i][j],f[i-1][j-1]+a[i]); if(i-j>=0)for(int k=0;k<=j;k++)f[i][0]=max(f[i][0],f[i-j][k]); } printf("%d\n",f[n][0]); return 0;}/*简单优化224ms*/#include<cstdio>#define maxn 10010using namespace std;int n,m,a[maxn],f[maxn][510];int max(int x,int y){ return x>y?x:y;}int main(){ scanf("%d%d",&n,&m); for(int i=1;i<=n;i++) scanf("%d",&a[i]); for(int i=1;i<=n;i++) for(int j=0;j<=m;j++){ if(j>0)f[i][j]=max(f[i][j],f[i-1][j-1]+a[i]); if(i-j>=0)f[i][0]=max(f[i][0],max(f[i-j][j],f[i-1][0])); } printf("%d\n",f[n][0]); return 0;}/*bzoj 1614 二分*/#include<iostream>#include<cstdio>#include<cstring>#include<queue>#define maxn 1010#define inf 0x3f3f3f3fusing namespace std;int n,m,k,num,head[maxn],f[maxn],dis[maxn],l,r,ans;struct node{ int v,t,pre;}e[maxn*20];queue<int>q;int init(){ int x=0;char s=getchar(); while(s<‘0‘||s>‘9‘)s=getchar(); while(s>=‘0‘&&s<=‘9‘){x=x*10+s-‘0‘;s=getchar();} return x;}void Add(int from,int to,int dis){ num++;e[num].v=to; e[num].t=dis; e[num].pre=head[from]; head[from]=num;}bool SPFA(int x){ for(int i=1;i<=n;i++)dis[i]=inf; q.push(1);f[1]=1;dis[1]=0; while(!q.empty()){ int k=q.front(); q.pop();f[k]=0; for(int i=head[k];i;i=e[i].pre){ int v=e[i].v,cost=0; if(e[i].t>x)cost++; if(dis[v]>dis[k]+cost){ dis[v]=dis[k]+cost; if(f[v]==0){ q.push(v);f[v]=1; } } } } return dis[n]<=k;}int main(){ n=init();m=init();k=init(); int u,v,t; for(int i=1;i<=m;i++){ u=init();v=init();t=init(); Add(u,v,t);Add(v,u,t);r=max(r,t); } ans=-1; while(l<=r){ int mid=(l+r)/2; if(SPFA(mid)){ r=mid-1; ans=mid; } else l=mid+1; } printf("%d\n",ans); return 0;}/*bzoj 1609 记忆化*/#include<iostream>#include<cstdio>#include<cstring>#define maxn 30010using namespace std;int n,a[maxn],f1[maxn][4],f2[maxn][4];int Dfs1(int now,int lim){ if(f1[now][lim]!=-1)return f1[now][lim]; if(now==n+1)return 0; int r=0x7fffffff; if(a[now]>=lim)r=min(r,Dfs1(now+1,a[now])); r=min(r,Dfs1(now+1,lim)+1); return f1[now][lim]=r;}int Dfs2(int now,int lim){ if(f2[now][lim]!=-1)return f2[now][lim]; if(now==n+1)return 0; int r=0x7fffffff; if(a[now]<=lim)r=min(r,Dfs2(now+1,a[now])); r=min(r,Dfs2(now+1,lim)+1); return f2[now][lim]=r;}int main(){ scanf("%d",&n); for(int i=1;i<=n;i++) scanf("%d",&a[i]); memset(f1,-1,sizeof(f1)); memset(f2,-1,sizeof(f2)); printf("%d\n",min(Dfs1(1,0),Dfs2(1,4)));}/*bzoj 1610 模拟*/#include<iostream>#include<cstdio>#include<cstring>#define maxn 210using namespace std;int n,x[maxn],y[maxn],ans;bool f[maxn*10][maxn*10][2];int Abs(int x){ return x<0?-x:x;}int Gcd(int a,int b){ return b==0?a:Gcd(b,a%b);}void Insert(int a,int b){ int c=0; if(a==0)b=1; else if(b==0)a=1; else{ if(a*b<0)c=1; int A=Abs(a),B=Abs(b); int gcd=Gcd(A,B); a=A/gcd;b=B/gcd; } if(f[a][b][c]==0)ans++; f[a][b][c]=1;}int main(){ //freopen("lines.in","r",stdin); //freopen("lines.out","w",stdout); scanf("%d",&n); for(int i=1;i<=n;i++) scanf("%d%d",&x[i],&y[i]); for(int i=1;i<=n;i++) for(int j=i+1;j<=n;j++){ int X=x[i]-x[j]; int Y=y[i]-y[j]; Insert(X,Y); } printf("%d\n",ans); return 0;}
9.29 奶牛练习题
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