首页 > 代码库 > [LeetCode #8] String to Integer (atoi)
[LeetCode #8] String to Integer (atoi)
Implement atoi to convert a string to an integer.
Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases.
Notes: It is intended for this problem to be specified vaguely (ie, no given input specs). You are responsible to gather all the input requirements up front.
1 int myAtoi(char *s){ 2 int ret = 0; 3 int i = 0; 4 int digit = 0; 5 int sign = 1; 6 7 while(s[i] && s[i] == ‘ ‘){ i++; } 8 if (s[i] == ‘+‘) {sign = 1; i++;} 9 else if (s[i] == ‘-‘) {sign = -1; i++;}10 11 while (s[i]){12 if ((s[i] <= ‘9‘) && (s[i] >= ‘0‘)){13 digit = s[i] - ‘0‘;14 }15 else{16 break;17 }18 if(2147483647/10 < ret || 2147483647/10 == ret && 2147483647%10 < (s[i] -‘0‘)) 19 {20 return sign == -1 ? (-2147483648) : 2147483647;21 } 22 ret = ret * 10 + digit; 23 i++;24 } 25 return ret * sign;26 }
[LeetCode #8] String to Integer (atoi)
声明：以上内容来自用户投稿及互联网公开渠道收集整理发布，本网站不拥有所有权，未作人工编辑处理，也不承担相关法律责任，若内容有误或涉及侵权可进行投诉： 投诉/举报 工作人员会在5个工作日内联系你，一经查实，本站将立刻删除涉嫌侵权内容。