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209. Minimum Size Subarray Sum

Given an array of n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn‘t one, return 0 instead.

For example, given the array [2,3,1,2,4,3] and s = 7,
the subarray [4,3] has the minimal length under the problem constraint.

 思路:经典的滑动窗口。右指针向右移动,如果和大于sum,记录size,比较是否存入min。然后将左指针右移,继续判断。

public class Solution {    public int minSubArrayLen(int s, int[] nums) {    if(nums.length==0)    {        return 0;    }    int i=0,j=0,sum=0;    int min=Integer.MAX_VALUE;    while(j<nums.length)    {        sum+=nums[j];        while(sum>=s)        {            min=Math.min(min,j-i+1);            sum-=nums[i];            i++;        }        j++;    }    if(min==Integer.MAX_VALUE)    {        return 0;    }    return min;    }}

 

209. Minimum Size Subarray Sum