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Android快速拨号匹配算法(二)
接上篇,下面是几个匹配算法的详情:
1.完全匹配
完全匹配很简单了,只要判断string是否相等就行了。这里要判断所有拼音和所有号码。如果拼音已经符合,就不再判断号码。反正是一个人……
private ScoreAndHits completeMatch(String reg) { ScoreAndHits scoreAndHits = new ScoreAndHits(-1, 0f, new ArrayList<PointPair>()); for (int i = 0; i < fullNameNumberWithoutSpace.size(); i++) { String str = fullNameNumberWithoutSpace.get(i); if (reg.equals(str)) { scoreAndHits.nameIndex = i; scoreAndHits.score = Match_Level_Complete; scoreAndHits.pairs.add(new PointPair(i, -1)); scoreAndHits.matchLevel = Level_Complete; return scoreAndHits; } } for (int i = 0; i < phones.size(); i++) { PhoneStruct phone = phones.get(i); if (reg.equals(phone.phoneNumber)) { scoreAndHits.nameIndex = i; scoreAndHits.score = Match_Level_Complete; scoreAndHits.pairs.add(new PointPair(i, -1)); scoreAndHits.matchType = Match_Type_Phone; scoreAndHits.matchLevel = Level_Complete; return scoreAndHits; } } // 走到这里说明没有匹配 return new ScoreAndHits(-1, 0f, new ArrayList<PointPair>()); }
2.前置首字母溢出匹配。(能不能想个好听的名字)
private ScoreAndHits foreAcronymOverFlowMatch(String reg) { // 因为有可能是多音字,所以这个方法用来对比不同拼音的匹配度,并取最大的那个 ScoreAndHits scoreAndHits = new ScoreAndHits(-1, 0f, new ArrayList<PointPair>()); for (int i = 0; i < fullNameNumber.size(); i++) { ArrayList<String> names = fullNameNumber.get(i); ScoreAndHits tmpscore = foreAcronymOverFlowMatch(names, reg); if (tmpscore.score > scoreAndHits.score) { scoreAndHits = tmpscore; scoreAndHits.nameIndex = i; } } scoreAndHits.matchLevel = Level_Fore_Acronym_Overflow; return scoreAndHits; } // 在第一个字母确定的情况下,第二个字母有可能有三种情况 // 一、在第一个字母所在单词的邻居位置charAt(x+1); // 二、在第二个单词的首字母处 // 三、以上两种情况皆不符合,不匹配,出局 private ScoreAndHits foreAcronymOverFlowMatch(ArrayList<String> names, String reg) { // 用来得出某一个拼音的匹配值。 ScoreAndHits scoreAndHits = new ScoreAndHits(-1, 0f, new ArrayList<PointPair>()); if (names.get(0).charAt(0) == reg.charAt(0)) { //其实crossWords()方法才是求匹配值的方法,lol OverflowMatchValue value = crossWords(names, reg, 0, 0, 0); int cross = crossWords(names, reg, 0, 0, 0).crossed; if (cross > 0) { scoreAndHits.score = Match_Level_Fore_Acronym_Overflow + cross * Match_Score_Reward - (names.size() - cross) * Match_Miss_Punish; scoreAndHits.pairs = value.pairs; } } return scoreAndHits; } /** * 返回一串字符能跨越另一串字符的长度,根据上面的匹配规则,要尽可能的多匹配单词。若要保证 * 能匹配最长的长度,只要保证下一个字符开始的一段字符能匹配 * 最长的长度即可,换名话说,如果想要让96758匹配最长的字符串,那么只要保证6758能匹配最长 * 的字符串即可,然后758,再然后58……。例如,名字叫PanAnNing,输入pan,那么应该匹配三个 * 首字母,PAN,而不是第一姓的拼音Pan. * 这是一个递归。 * * @param names * @param regString * 匹配字符串 * @param listIndex * 匹配到的list的第listIndex个单词 * @param strIndex * 匹配到第listIndex个单词中的第strIndex个字母 * @param regIndex * regchar的匹配位置,比如匹配到了96758的7上,也就是regIndex==2. * @return */ private OverflowMatchValue crossWords(ArrayList<String> names, String regString, int listIndex, int strIndex, int regIndex) { OverflowMatchValue result = new OverflowMatchValue(0, false); OverflowMatchValue reser = new OverflowMatchValue(0, false); OverflowMatchValue impul = new OverflowMatchValue(0, false); if (regIndex < regString.length() - 1) { char nextChar = regString.charAt(regIndex + 1); if (listIndex < names.size() - 1 && nextChar == names.get(listIndex + 1).charAt(0)) { impul = crossWords(names, regString, listIndex + 1, 0, regIndex + 1); } if (strIndex < names.get(listIndex).length() - 1 && nextChar == names.get(listIndex).charAt(strIndex + 1)) { reser = crossWords(names, regString, listIndex, strIndex + 1, regIndex + 1); } } else { result = new OverflowMatchValue((strIndex == 0) ? 1 : 0, true); result.pairs.add(0, new PointPair(listIndex, strIndex)); } if (reser.matched || impul.matched) { if (impul.crossed > reser.crossed) { result = impul; } else { result = reser; } result.matched = true; result.crossed = ((strIndex == 0) ? 1 : 0) + Math.max(result.crossed, result.crossed); result.pairs.add(0, new PointPair(listIndex, strIndex)); } return result; } static class OverflowMatchValue { public int crossed = 0; public boolean matched = false; public ArrayList<PointPair> pairs = new ArrayList<PointPair>(); public OverflowMatchValue(int c, boolean m) { this.crossed = c; this.matched = m; } }
3.后置首字母溢出匹配。(能不能想个好听的名字)
跟前置首字母溢出匹配基本一样,只不过匹配的第一个字母不再是姓的首字母。
private ScoreAndHits backAcronymOverFlowMatch(String reg) { //跟上面差不多 ScoreAndHits scoreAndHits = new ScoreAndHits(-1, 0f, new ArrayList<PointPair>()); for (int i = 0; i < fullNameNumber.size(); i++) { ArrayList<String> names = fullNameNumber.get(i); ScoreAndHits tmp = backAcronymOverFlowMatch(names, reg); if (tmp.score > scoreAndHits.score) { scoreAndHits = tmp; scoreAndHits.nameIndex = i; } } scoreAndHits.matchLevel = Level_Back_Acronym_Overflow; return scoreAndHits; } private ScoreAndHits backAcronymOverFlowMatch(ArrayList<String> names, String reg) { int score = 0; int punish = 0; ScoreAndHits scoreAndHits = new ScoreAndHits(-1, 0f, new ArrayList<PointPair>()); // 有可能会调用多次crossWords,取决于名字的长度。这是跟前面的不同 for (int i = 0; i < names.size(); i++) { String string = (String) names.get(i); if (string.charAt(0) == reg.charAt(0)) { OverflowMatchValue value = crossWords(names, reg, i, 0, 0); int cross = value.crossed; int lost = names.size() - cross; if (cross > score || cross == score && punish > lost) { scoreAndHits.pairs = value.pairs; score = cross; punish = lost; } } } if (score > 0) { scoreAndHits.score = Match_Level_Back_Acronym_Overflow + score * Match_Score_Reward - punish * Match_Miss_Punish; return scoreAndHits; } else { return new ScoreAndHits(-1, 0f, new ArrayList<PointPair>()); } }
4.后置无头匹配。(难听就难听了,反正就那个意思)
private ScoreAndHits backHeadlessParagraphMatch(String reg) { int punish = 0; ScoreAndHits scoreAndHits = new ScoreAndHits(-1, -1f, new ArrayList<PointPair>()); scoreAndHits.matchLevel = Level_Headless; scoreAndHits.matchType = Match_Type_Phone; // 算了不匹配姓名了,假设没人会得这么离谱 for (int i = 0; i < phones.size(); i++) { PhoneStruct phone = phones.get(i); int sco = phone.phoneNumber.indexOf(reg); if (sco >= 0) { int lost = phone.phoneNumber.length() - reg.length(); if (scoreAndHits.score < sco || sco == scoreAndHits.score && punish > lost) { scoreAndHits.score = sco; scoreAndHits.nameIndex = i; // 尽管有可能匹配的字符串很长,但是因为是连贯的,所以只要 // add一个就够啦 scoreAndHits.pairs.add(new PointPair(i, sco)); punish = lost; } } } if (scoreAndHits.score >= 0) { scoreAndHits.score = Match_Level_Headless - scoreAndHits.score * Match_Score_Reward - punish * Match_Miss_Punish; } return scoreAndHits; }
到这里已经可以得出输入字符串与联系人的匹配度了,剩下的事情就是调用和显示了,但是这不是本文的重点
本文出自 “NashLegend” 博客,请务必保留此出处http://nashlegend.blog.51cto.com/5635342/1566111
Android快速拨号匹配算法(二)
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