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Java 模拟双端链表
双端链表:
双端链表与传统链表非常相似.只是新增了一个属性-即对最后一个链结点的引用rear
这样在链尾插入会变得非常容易,只需改变rear的next为新增的结点即可,而不需要循环搜索到最后一个节点
所以有insertFirst、insertLast
删除链头时,只需要改变引用指向即可;删除链尾时,需要将倒数第二个结点的next置空,
而没有一个引用是指向它的,所以还是需要循环来读取操作
/** * 双端链表 * @author stone */ public class TwoEndpointList<T> { private Link<T> head; //首结点 private Link<T> rear; //尾部指针 public TwoEndpointList() { } public T peekHead() { if (head != null) { return head.data; } return null; } public boolean isEmpty() { return head == null; } public void insertFirst(T data) {// 插入 到 链头 Link<T> newLink = new Link<T>(data); newLink.next = head; //新结点的next指向上一结点 head = newLink; } public void insertLast(T data) {//在链尾 插入 Link<T> newLink = new Link<T>(data); if (rear != null) { rear.next = newLink; } else { head = newLink; head.next = rear; } rear = newLink; //下次插入时,从rear处插入 } public T deleteHead() {//删除 链头 if (isEmpty()) return null; Link<T> temp = head; head = head.next; //变更首结点,为下一结点 if (head != null && head.next == null) { rear = head; } return temp.data; } public T find(T t) { if (isEmpty()) { return null; } Link<T> find = head; while (find != null) { if (!find.data.equals(t)) { find = find.next; } else { break; } } if (find == null) { return null; } return find.data; } public T delete(T t) { if (isEmpty()) { return null; } else { if (head.data.equals(t)) { Link<T> temp = head; head = head.next; //变更首结点,为下一结点 return temp.data; } } Link<T> p = head; Link<T> q = head; while (!p.data.equals(t)) { if (p.next == null) {//表示到链尾还没找到 return null; } else { q = p; p = p.next; } } q.next = p.next; return p.data; } public void displayList() {//遍历 System.out.println("List (head-->last):"); Link<T> current = head; while (current != null) { current.displayLink(); current = current.next; } } public void displayListReverse() {//反序遍历 if (isEmpty()) { return; } Link<T> p = head, q = head.next, t; while (q != null) {//指针反向,遍历的数据顺序向后 t = q.next; //no3 if (p == head) {// 当为原来的头时,头的.next应该置空 p.next = null; } q.next = p;// no3 -> no1 pointer reverse p = q; //start is reverse q = t; //no3 start } //上面循环中的if里,把head.next 置空了, 而当q为null不执行循环时,p就为原来的最且一个数据项,反转后把p赋给head head = p; displayList(); } class Link<T> {//链结点 T data; //数据域 Link<T> next; //后继指针,结点 链域 Link(T data) { this.data = http://www.mamicode.com/data;>打印List (head-->last): the data is 4 the data is 2 the data is 1 the data is 3 the data is 5 List (head-->last): the data is 2 the data is 1 the data is 3 the data is 5 find:null find:3 delete find:null delete find:5 List (head-->last): the data is 2 the data is 1 the data is 3 ----reverse---- List (head-->last): the data is 3 the data is 1 the data is 2/** * 使用链表实现栈 * @author stone * */ public class LinkStack<T> { private TwoEndpointList<T> datas; public LinkStack() { datas = new TwoEndpointList<T>(); } // 入栈 public void push(T data) { datas.insertFirst(data); } // 出栈 public T pop() { return datas.deleteHead(); } // 查看栈顶 public T peek() { return datas.peekHead(); } //栈是否为空 public boolean isEmpty() { return datas.isEmpty(); } public static void main(String[] args) { LinkStack<Integer> stack = new LinkStack<Integer>(); for (int i = 0; i < 5; i++) { stack.push(i); } for (int i = 0; i < 5; i++) { Integer peek = stack.peek(); System.out.println("peek:" + peek); } for (int i = 0; i < 6; i++) { Integer pop = stack.pop(); System.out.println("pop:" + pop); } System.out.println("----"); for (int i = 5; i > 0; i--) { stack.push(i); } for (int i = 5; i > 0; i--) { Integer peek = stack.peek(); System.out.println("peek:" + peek); } for (int i = 5; i > 0; i--) { Integer pop = stack.pop(); System.out.println("pop:" + pop); } } }打印peek:4 peek:4 peek:4 peek:4 peek:4 pop:4 pop:3 pop:2 pop:1 pop:0 pop:null ---- peek:1 peek:1 peek:1 peek:1 peek:1 pop:1 pop:2 pop:3 pop:4 pop:5Java 模拟双端链表
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