来源于ISCC 2012 破解关第四题 

目的是通过逆向police。实现一个thief,可以与police进行通信

实际上就是一个ＲＳＡ加密通信的样例，我们通过自己编写client和服务端来实现上面的thief和police的功能．．

要通信。这们这次先通过python写出能够进行网络连接的client与服务端．．

服务端代码

#!/usr/bin/env python 
import SocketServer 
from time import ctime 
HOST = ‘127.0.0.1‘
PORT = 2012 
ADDR = (HOST, PORT) 
class MyRequestHandler(SocketServer.BaseRequestHandler):
        def handle(self):
                print ‘...connected from...‘, self.client_address
                while True: 
                        self.request.sendall(‘[%s] %s‘ % (ctime(),self.request.recv(1024)))


tcpServ = SocketServer.ThreadingTCPServer(ADDR, MyRequestHandler) 
print ‘waiting for connection...‘ 
tcpServ.serve_forever()

#!/usr/bin/env python 
from socket import * 
HOST = ‘127.0.0.1‘ 
PORT = 2012 
BUFSIZ = 1024 
ADDR = (HOST, PORT) 

tcpCliSock = socket(AF_INET, SOCK_STREAM) 
tcpCliSock.connect(ADDR) 
while True: 
    data = raw_input(‘>>>>>>>>>>>>‘) 
    if not data: 
        break 
    tcpCliSock.send(‘%s\r\n‘ % data) 
    data = tcpCliSock.recv(BUFSIZ) 
    if not data: 
        break 
    print data.strip() 
#tcpCliSock.close()

假设报python errno 10053错误，请确认下client的连接代码一定要在循环外

也就是

tcpCliSock = socket(AF_INET, SOCK_STREAM) 
tcpCliSock.connect(ADDR) 

下次解决ＲＳＡ加密的问题