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LeetCode-Substring with Concatenation of All Words

题目:

You are given a string, S, and a list of words, L, that are all of the same length. Find all starting indices of substring(s) in S that is a concatenation of each word in L exactly once and without any intervening characters.

For example, given:
S: "barfoothefoobarman"
L: ["foo", "bar"]

You should return the indices: [0,9].

源码:

用两个map,其中一个map用来保存L中每个word出现的次数。然后遍历S字符串,通过比较word_counts中的单词出现的次数.若超过或不出现则break.

vector<int> findSubstring(string S,vector<string> &L){      int size=L.size();      if(size<=0) return vector<int>();            map<string,int> word_counts;      for(int i=0;i<size;i++){          word_counts[L[i]]++;      }            int word_size=L[0].size();      map<string,int> counting;      vector<int> result;            for(int i=0;i<=((int)S.length()-size*word_size);i++){            counting.clear();                        for(int j=0;j<size;j++){                 string word=S.substr(i+j*word_size,word_size);                                  if(word_counts.find(word)!=word_counts.end()){                        counting[word]++;                                                if(counting[word]>word_counts[word]) break;                 }                             }                        if(j==size) result,push_back(i);      }      return result;}

 

LeetCode-Substring with Concatenation of All Words