首页 > 代码库 > HDU1098 Ignatius's puzzle 【数论】
HDU1098 Ignatius's puzzle 【数论】
Ignatius‘s puzzle
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 6559 Accepted Submission(s): 4540
Problem Description
Ignatius is poor at math,he falls across a puzzle problem,so he has no choice but to appeal to Eddy. this problem describes that:f(x)=5*x^13+13*x^5+k*a*x,input a nonegative integer k(k<10000),to find the minimal nonegative integer a,make the arbitrary integer x ,65|f(x)if
no exists that a,then print "no".
no exists that a,then print "no".
Input
The input contains several test cases. Each test case consists of a nonegative integer k, More details in the Sample Input.
Output
The output contains a string "no",if you can‘t find a,or you should output a line contains the a.More details in the Sample Output.
Sample Input
11 100 9999
Sample Output
22 no 43
Author
eddy
题意:求出使x为任意值时f(x)都能被65整除的最小a的值,若不存在输出no。
题解:若任意f(x)都能被65整除,那么f(1)%65==0,(f(x+1)-f(x))%65 == 0,二项式展开得(18+k*a)%65 == 0,所以只需要遍历找到a即可。
#include <stdio.h> int main() { int k, a; while(~scanf("%d", &k)) { for(a = 0; a <= 65; ++a) if((18 + k*a) % 65 == 0) { printf("%d\n", a); break; } if(a > 65) printf("no\n"); } return 0; }
HDU1098 Ignatius's puzzle 【数论】
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。