字符串题目就先告一段落了，又是在看balabala不知道在说些什么的英语。

算法也很简单，用了几个库函数就搞定了。本来还担心题里说的replace-by为空的特殊情况需要特殊处理，后来发现按一般情况处理也能A过去。

第一次RE是因为char t[]开小了。

对了，strstr()函数我也是第一次用，对这个函数不太了解的同学，召唤传送门！

C语言中字符串操作之 strstr()

题目大意：给几组要查找的和要替换的字符串，和一段text，进行查找替换。说白了就是word里面查找替换功能。

不过需要注意的一点就是Find被替换完以后可能会出现新的Find子串，即Find可能被替换多次。

Problem E: Automatic Editing

Text-processing tools like awk and sed allow you to automatically perform a sequence of editing operations based on a script. For this problem we consider the specific case in which we want to perform a series of string replacements, within a single line of text, based on a fixed set of rules. Each rule specifies the string to find, and the string to replace it with, as shown below.

Rule	Find	Replace-by
1.	ban	bab
2.	baba	be
3.	ana	any
4.	ba b	hind the g

To perform the edits for a given line of text, start with the first rule. Replace the first occurrence of the find string within the text by the replace-by string, then try to perform the same replacement again on the new text. Continue until the find string no longer occurs within the text, and then move on to the next rule. Continue until all the rules have been considered. Note that (1) when searching for a find string, you always start searching at the beginning of the text, (2) once you have finished using a rule (because thefind string no longer occurs) you never use that rule again, and (3) case is significant.

For example, suppose we start with the line

banana boat

and apply these rules. The sequence of transformations is shown below, where occurrences of a find string are underlined and replacements are boldfaced. Note that rule 1 was used twice, then rule 2 was used once, then rule 3 was used zero times, and then rule 4 was used once.

	Before	After
	banana boat	babana boat
	babana boat	bababa boat
	bababa boat	beba boat
	beba boat	behind the goat

The input contains one or more test cases, followed by a line containing only 0 (zero) that signals the end of the file. Each test case begins with a line containing the number of rules, which will be between 1 and 10. Each rule is specified by a pair of lines, where the first line is the find string and the second line is the replace-by string. Following all the rules is a line containing the text to edit. For each test case, output a line containing the final edited text.

Both find and replace-by strings will be at most 80 characters long. Find strings will contain at least one character, but replace-by strings may be empty (indicated in the input file by an empty line). During the edit process the text may grow as large as 255 characters, but the final output text will be less than 80 characters long.

The first test case in the sample input below corresponds to the example shown above.

Example input:

4banbabbababeanaanyba bhind the gbanana boat1tshtoe or top0

Example output:

behind the goatshoe or shop

AC代码：

 1 //#define LOCAL 2 #include <iostream> 3 #include <cstdio> 4 #include <cstring> 5 using namespace std; 6  7 char Find[11][85],  Replace[11][85]; 8 char text[260]; 9 10 int main(void)11 {12     #ifdef LOCAL13         freopen("10115in.txt", "r", stdin);14     #endif15     int N;16     while(scanf("%d", &N) == 1 && N)17     {18         getchar();19         int i;20         for(i = 0; i < N; ++i)21         {22             gets(Find[i]);23             gets(Replace[i]);24         }25         memset(text, 0, sizeof(text));26         gets(text);27         28         char *s, t[260];//一开始开的85，然后RE了29         for(i = 0; i < N; ++i)30         {31             while(s = strstr(text, Find[i]))//一个Find[i]可能要被替换多次32             {33                 strcpy(t, s + strlen(Find[i]));//把后面需要连接的字符串先暂存在t里面34                 *s = ‘\0‘;35                 //if(strlen(Replace[i]))// strlen(Replace[i]) == 0 按一般情况处理即可36                 //{37                     strcat(text, Replace[i]);//连接需要替换的字符串38                     strcat(text, t);        //连接最后的小尾巴39                 //}40                 //else41                     //strcat(text, t);42             }43         }44 45         cout << text << endl;46     }47     return 0;48 }

代码君