首页 > 代码库 > C#使用栈进行十以内的进制转换

C#使用栈进行十以内的进制转换

static void Main(string[] args) {            int n,m;            while (true) {                Console.WriteLine("请输入要转换的数和进制,用英文空格分开:");                string s = Console.ReadLine();                string[] str = s.Split( );                n = Convert.ToInt32( str[0] );                m = Convert.ToInt32( str[1] );                Console.WriteLine(n+"的m进制为:"+test3(n,m));}public static string test3(int num, int fomat) {            Stack s = new Stack();            while (num != 0) {                int t = num % fomat;                s.Push(t);                num = (num-t)/fomat;            }            int n = s.Count;            string res = "";            for (int i = 0; i < n; i++) {                res += s.Pop();            }            return res;}

技术分享

C#使用栈进行十以内的进制转换