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hibernate:is not mapped

报错提示为:org.hibernate.hql.ast.QuerySyntaxException: customers is not mapped [from customers as c]

服务层代码 为:

public void findCustomerAndOrders(){        Session session = sessionFactory.openSession();        Transaction tx = null;        try {            tx = session.beginTransaction();            Query query = session.createQuery("from customers as c");            List list = query.list();            for(int i = 0 ;i<list.size();i++){                Customers c = (Customers) list.get(i);                System.out.println(":"+c.getId());                System.out.println(":"+c.getName());                System.out.println(":"+c.getAddress());                Iterator it = c.getOrderses().iterator();                while(it.hasNext()){                    Orders order = (Orders)it.next();                    System.out.println(order.getOrderNumber()+"  ");                }                System.out.println("  ");            }            tx.commit();        } catch(Exception e ){            if(tx!=null){                tx.rollback();            }            e.printStackTrace();        } finally {            session.close();        }    }

hibernate配置文件为:

<?xml version="1.0" encoding="utf-8"?><!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN""http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"><!--     Mapping file autogenerated by MyEclipse Persistence Tools--><hibernate-mapping>    <class name="com.yehancheng.bean.Customers" table="customers">        <id name="id" type="java.lang.Integer">            <column name="id" />            <generator class="native" />        </id>        <property name="name" type="java.lang.String">            <column name="name" not-null="true" />        </property>        <property name="address" type="java.lang.String">            <column name="address" not-null="true" />        </property>        <set name="orderses" inverse="true" cascade="all">            <key>                <column name="customerId" not-null="true" />            </key>            <one-to-many class="com.yehancheng.bean.Orders" ></one-to-many>        </set>    </class></hibernate-mapping>

而出现这个错误的根本原因是hql语法里面是POJO对象而不是table.所以改成这样就可以了:

 Query query = session.createQuery("from Customers as c");