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【好】strong-password-checker,我自己做出来的:)
我自己做出来的,分了几种情况来考虑。(再后面有加了注释的版本)
https://leetcode.com/problems/strong-password-checker/ // 加油! public class Solution { public int strongPasswordChecker(String s) { int sLen = s.length(); if (sLen < 4) { return 6 - sLen; } int lnum = 1; int unum = 1; int dnum = 1; int rcount = 0; int ricount = 0; int rdcount = 0; int sameseq = 0; for (int i=0; i<sLen; i++) { char ch = s.charAt(i); if (ch>=‘a‘ && ch<=‘z‘) { lnum = 0; } if (ch>=‘A‘ && ch<=‘Z‘) { unum = 0; } if (ch>=‘0‘ && ch<=‘9‘) { dnum = 0; } // fix bug if (i == 0) { sameseq = 1; } else if (ch != s.charAt(i-1)) { if (sameseq >= 3) { // 这个很重要 while (sLen + ricount < 6 && sameseq >= 3) { ricount++; sameseq -= 2; } while (sLen - rdcount > 20 && sameseq >= 3) { rdcount++; sameseq --; } rcount += sameseq / 3; } sameseq = 1; } else { sameseq++; } } // fixbug if (sameseq >= 3) { // 这个很重要 while (sLen + ricount < 6 && sameseq >= 3) { ricount++; sameseq -= 2; } while (sLen - rdcount > 20 && sameseq >= 3) { rdcount++; sameseq --; } rcount += sameseq / 3; } //System.out.printf("rcount: %d, ricount: %d, rdcount: %d, lnum: %d, unum: %d, dnum: %d\n", // rcount, ricount, rdcount, lnum, unum, dnum); int update = lnum + unum + dnum; int must = ricount + rcount; if (sLen + ricount < 6) { must += 6 - sLen - ricount; } if (sLen < 20) { return must > update ? must : update; } // 跟上面的不一样,因为删除字符是无法增加新的类型的 if (sLen - rdcount > 20) { rdcount += sLen - rdcount - 20; } return rcount >= update ? rcount + rdcount : update + rdcount; } }
以下是加了注释的版本:
public class Solution { public int strongPasswordChecker(String s) { int sLen = s.length(); if (sLen < 4) { return 6 - sLen; } int lnum = 1; // need lower int unum = 1; // need upper int dnum = 1; // need digit int rcount = 0; // count need to replace repeated seq int ricount = 0; // count need to add in repeated seq int rdcount = 0; // count need to remove from repeated seq int sameseq = 0; // count of chars in repeated seq for (int i=0; i<sLen; i++) { char ch = s.charAt(i); if (ch>=‘a‘ && ch<=‘z‘) { lnum = 0; } if (ch>=‘A‘ && ch<=‘Z‘) { unum = 0; } if (ch>=‘0‘ && ch<=‘9‘) { dnum = 0; } // check repeated seq if (i == 0) { sameseq = 1; } else if (ch != s.charAt(i-1)) { if (sameseq >= 3) { // if shorter length, add char into repeated seq while (sLen + ricount < 6 && sameseq >= 3) { ricount++; sameseq -= 2; } // if longer length, remove char from repeated seq while (sLen - rdcount > 20 && sameseq >= 3) { rdcount++; sameseq --; } // if length matches, replace char in repeated seq rcount += sameseq / 3; } sameseq = 1; } else { sameseq++; } } // need check repeated seq after loop if (sameseq >= 3) { // as previous process while (sLen + ricount < 6 && sameseq >= 3) { ricount++; sameseq -= 2; } while (sLen - rdcount > 20 && sameseq >= 3) { rdcount++; sameseq --; } rcount += sameseq / 3; } int update = lnum + unum + dnum; int must = ricount + rcount; if (sLen + ricount < 6) { must += 6 - sLen - ricount; } if (sLen < 20) { return must > update ? must : update; } // if longer length, use below process if (sLen - rdcount > 20) { rdcount += sLen - rdcount - 20; } return rcount >= update ? rcount + rdcount : update + rdcount; } }
准备发表在Discuss版:
https://discuss.leetcode.com/category/549/strong-password-checker
【好】strong-password-checker,我自己做出来的:)
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