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[py]简易pick lucky num程序
程序功能:
1,用户输入数字,当用户输入指定数字时候,输出他输入的循环那次
2,第二次询问是否还要输
3,如果no 则 终止
4,如果yes则继续输入
判断输入是否大于首次输入的
如果大于则开始循环输出他第二次的lucky num
否则循环让输入,直到它输入为大于首次
#!/usr/bin/env python####coding:utf8lucky_num=input(‘lucky_num:‘)count=1while count < 100000: # count+=1 print ‘loop:‘,count if lucky_num==count: print ‘you have got your lucky num:‘,count op=raw_input("if you want to continue(y/n):") if op=="n":break else: while 1: lucky_num_new=input(‘lucky_num:‘) if lucky_num>lucky_num_new: print "too small,you should bigger than %s pls reinput your lucky num:"% lucky_num else: lucky_num=lucky_num_new break # print ‘loop:‘,count count+=1else: print ‘wow. that fantastic‘,count
执行结果:
py@lanny:~/t$ python t.py lucky_num:5loop: 1loop: 2loop: 3loop: 4loop: 5you have got your lucky num: 5if you want to continue(y/n):ylucky_num:3too small,you should bigger than 5 pls reinput your lucky num:lucky_num:2too small,you should bigger than 5 pls reinput your lucky num:lucky_num:4too small,you should bigger than 5 pls reinput your lucky num:lucky_num:9loop: 6loop: 7loop: 8loop: 9you have got your lucky num: 9if you want to continue(y/n):
[py]简易pick lucky num程序
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