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快速排序的实现(c语言)

2024-07-05 22:46:31   223人阅读

以前写的代码

 

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//
//  main.c
//  cTest
//
//  Created by Zizhu on 13-10-8.
//  Copyright (c) 2013年 Zizhu. All rights reserved.
//
 
#include <stdio.h>
 
#define N (10)
 
void quickSor(int *nums, int indexStart, int indexEnd);
int  partition(int *nums, int indexStart, int indexEnd);
void exchange(int *nums, int p1, int p2);
void printNums(int *nums, int count);
 
int main()
{
    printf(">>>strat\n");
    int nums[N] = {0, 4, 2, 5, 1, 3, -1, 19, 99, -100};
    printNums(nums, N);
    int mid = partition(nums, 0, N-1);
    printNums(nums, N);
    printf("mid = %d\n", mid);
    quickSor(nums, 0, N-1);
    printNums(nums, N);
    return 0;
}
 
void quickSor(int *nums, int indexStart, int indexEnd)
{
    if (indexEnd > indexStart)
    {
        int indexMid = partition(nums, indexStart, indexEnd);
        quickSor(nums, indexStart, indexMid-1);
        quickSor(nums, indexMid+1, indexEnd);
    }
     
}
 
int partition(int *nums, int indexStart, int indexEnd)
{
     
    int p2 = indexStart-1;
    int p1;
     
    int target = nums[indexEnd];
     
    for (p1 = indexStart; p1 < indexEnd; p1++)
    {
        if (nums[p1] <= target)
        {
            p2++;
            exchange(nums, p1, p2);
             
        }
    }
    exchange(nums, p2+1, indexEnd);
    return p2+1;
}
 
void exchange(int *nums, int p1, int p2)
{
    int tmp = nums[p1];
    nums[p1] = nums[p2];
    nums[p2] = tmp;
}
 
void printNums(int *nums, int count)
{
    printf("numbers : ");
    int i;
    for (i = 0; i < count; ++i)
    {
        printf("%4d\t", nums[i]);
    }
    printf("\n");
}

　　


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