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Gym 100851E Easy Problemset (水题,模拟)
题意:给定 n 个裁判,然后每个都一些题目,现在要从每一个按顺序去选出 k 个题,并且这 k 个要按不递减顺序,如果没有,就用50补充。
析:就按他说的来,直接模拟就好。
代码如下:
#pragma comment(linker, "/STACK:1024000000,1024000000")#include <cstdio>#include <string>#include <cstdlib>#include <cmath>#include <iostream>#include <cstring>#include <set>#include <queue>#include <algorithm>#include <vector>#include <map>#include <cctype>#include <cmath>#include <stack>#define freopenr freopen("in.txt", "r", stdin)#define freopenw freopen("out.txt", "w", stdout)using namespace std;typedef long long LL;typedef pair<int, int> P;const int INF = 0x3f3f3f3f;const double inf = 0x3f3f3f3f3f3f;const LL LNF = 0x3f3f3f3f3f3f;const double PI = acos(-1.0);const double eps = 1e-8;const int maxn = 1e5 + 5;const int mod = 1e9 + 7;const int dr[] = {-1, 0, 1, 0};const int dc[] = {0, 1, 0, -1};const char *Hex[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};int n, m;const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};inline int Min(int a, int b){ return a < b ? a : b; }inline int Max(int a, int b){ return a > b ? a : b; }inline LL Min(LL a, LL b){ return a < b ? a : b; }inline LL Max(LL a, LL b){ return a > b ? a : b; }inline bool is_in(int r, int c){ return r >= 0 && r < n && c >= 0 && c < m;}struct node{ int val, id; node(int v, int i) : val(v), id(i) { }};int a[15][15];int main(){ freopen("easy.in", "r", stdin); freopen("easy.out", "w", stdout); int k; while(scanf("%d %d", &n, &k) == 2){ int x = 0; memset(a, -1, sizeof a); for(int i = 0; i < n; ++i){ scanf("%d", &m); x = Max(x, m); for(int j = 0; j < m; ++j) scanf("%d", a[i]+j); } int cnt = 0, ans = 0; for(int i = 0; i < x && cnt < k; ++i){ for(int j = 0; j < n && cnt < k; ++j) if(a[j][i] >= ans){ ans += a[j][i]; ++cnt; } else if(a[j][i] == -1) { ans += 50; ++cnt; break; } } while(cnt < k) ans += 50, ++cnt; printf("%d\n", ans); } return 0;}
Gym 100851E Easy Problemset (水题,模拟)
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