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CodeForces 718A Efim and Strange Grade (贪心)
题意:给定一个浮点数,让你在时间 t 内,变成一个最大的数,操作只有把某个小数位进行四舍五入,每秒可进行一次。
析:贪心策略就是从小数点开始找第一个大于等于5的,然后进行四舍五入,完成后再看看是不是还可以,一循环下去,直到整数位,或者没时间了。
代码如下:
#pragma comment(linker, "/STACK:1024000000,1024000000")#include <cstdio>#include <string>#include <cstdlib>#include <cmath>#include <iostream>#include <cstring>#include <set>#include <queue>#include <algorithm>#include <vector>#include <map>#include <cctype>#include <cmath>#include <stack>#include <tr1/unordered_map>#define freopenr freopen("in.txt", "r", stdin)#define freopenw freopen("out.txt", "w", stdout)using namespace std;using namespace std :: tr1;typedef long long LL;typedef pair<int, int> P;const int INF = 0x3f3f3f3f;const double inf = 0x3f3f3f3f3f3f;const LL LNF = 0x3f3f3f3f3f3f;const double PI = acos(-1.0);const double eps = 1e-8;const int maxn = 2e5 + 5;const int mod = 1e9 + 7;const int N = 1e6 + 5;const int dr[] = {-1, 0, 1, 0, 1, 1, -1, -1};const int dc[] = {0, 1, 0, -1, 1, -1, 1, -1};const char *Hex[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};inline LL gcd(LL a, LL b){ return b == 0 ? a : gcd(b, a%b); }int n, m;const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};inline int Min(int a, int b){ return a < b ? a : b; }inline int Max(int a, int b){ return a > b ? a : b; }inline LL Min(LL a, LL b){ return a < b ? a : b; }inline LL Max(LL a, LL b){ return a > b ? a : b; }inline bool is_in(int r, int c){ return r >= 0 && r < n && c >= 0 && c < m;}char s[maxn];int a[maxn], b[maxn];int main(){ while(scanf("%d %d", &n, &m) == 2){ scanf("%s", s); int cnta = 0, cntb = 0; a[0] = b[0] = 0; bool ok = false; for(int i = 0; i < n; ++i){ if(s[i] == ‘.‘){ ok = true; continue; } if(ok) b[++cntb] = s[i] - ‘0‘; else a[++cnta] = s[i] - ‘0‘; } int cnt = 0; int y = 1, z = cntb; while(m--){ ok = false; bool x = true; for(int i = y; i <= z; ++i){ if(b[i] >= 5){ x = false; cnt = 1; ok = true; b[i] = -1; for(int j = i-1; j >= 0; --j){ if(b[j] + cnt > 9){ b[j] = -1; z = j; } else { b[j] += cnt; y = j; cnt = 0; break; } } } if(ok) break; } if(x) break; } if(b[0]){ cnt = 1; for(int j = cnta; j >= 0; --j){ if(a[j] + cnt > 9) a[j] = 0, cnt = 1; else { a[j] += cnt; cnt = 0; break; } } if(a[0]) printf("1"); for(int i = 1; i <= cnta; ++i) printf("%d", a[i]); } else{ int t = 0; for(int i = 1; i <= cntb; ++i) if(b[i] == -1){ t = i; break; } if(!t) t = cntb; for(int i = t; i > 0; --i) if(b[i] == 0 || b[i] == -1) b[i] = -1; else break; for(int i = 1; i <= cnta; ++i) printf("%d", a[i]); if(b[1] != -1){ printf("."); for(int i = 1; i <= cntb; ++i) if(b[i] == -1) break; else printf("%d", b[i]); } } printf("\n"); } return 0;}
CodeForces 718A Efim and Strange Grade (贪心)
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