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LeetCode64 Minimum Path Sum

题目:

Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.

Note: You can only move either down or right at any point in time.(Medium)

分析:

矩阵型动态规划,dp[i][j]表示到达i,j位置的。。。。

所以本题中dp[i][j]表示到达grid[i][j]的最小和。dp[i][j] = dp[i -1][j] + dp[i][j - 1];

代码:

 1 class Solution { 2 public: 3     int minPathSum(vector<vector<int>>& grid) { 4         int dp[grid.size()][grid[0].size()]; 5         dp[0][0] = grid[0][0]; 6         for (int i = 1; i < grid.size(); ++i) { 7             dp[i][0] = dp[i - 1][0] + grid[i][0]; 8         } 9         for (int i = 1; i < grid[0].size(); ++i) {10             dp[0][i] = dp[0][i - 1] + grid[0][i];11         }12         for (int i = 1; i < grid.size(); ++i) {13             for (int j = 1; j < grid[0].size(); ++j) {14                 dp[i][j] = min(dp[i - 1][j], dp[i][j - 1]) + grid[i][j];15             }16         }17         return dp[grid.size() - 1][grid[0].size() - 1];18     }19 };

 

LeetCode64 Minimum Path Sum