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leetcode--Remove Duplicates from Sorted List II
Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
For example,
Given 1->2->3->3->4->4->5
, return 1->2->5
.
Given 1->1->1->2->3
, return 2->3
.
?
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 | /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { * val = x; * next = null; * } * } */ public class Solution { public ListNode deleteDuplicates(ListNode head) { ListNode newHead = new ListNode( 0 ); ListNode currentNode = newHead; ListNode first = head; boolean distinct = true ; while (first != null ){ if (first.next != null ){ if (first.val == first.next.val) distinct = false ; else { if (distinct){ currentNode.next = first; currentNode = currentNode.next; } else distinct = true ; } } //the last node else { if (distinct){ currentNode.next = first; currentNode = currentNode.next; } } first = first.next; } currentNode.next = null ; newHead = newHead.next; return newHead; } } |
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