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Spring URL重写
1.利用maven下载相关jar文件,pom文件配置如下:
<dependency>
<groupId>org.tuckey</groupId>
<artifactId>urlrewritefilter</artifactId>
<version>4.0.4</version>
</dependency>
2.在web.xml中配置UrlRewriteFilter,配置如下:
<filter>
<filter-name>UrlRewriteFilter</filter-name>
<filter-class>org.tuckey.web.filters.urlrewrite.UrlRewriteFilter</filter-class>
<!-- 因为urlrewrite.xml只能在web-inf下,所以我们这里可以省略掉urlrewrite.xml的路径配置。 -->
<init-param>
<param-name>logLevel</param-name>
<param-value>WARN</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>UrlRewriteFilter</filter-name>
<url-pattern>/*</url-pattern>
<dispatcher>REQUEST</dispatcher>
<dispatcher>FORWARD</dispatcher>
</filter-mapping>
3.添加urlrewirte.xml文件,将文件放在WEB-INF目录下(貌似该文件只能放在WEB-INF下)。配置如下:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE urlrewrite PUBLIC "-//tuckey.org//DTD UrlRewrite 3.2//EN" "\\urlrewrite3.2.dtd">
<urlrewrite>
<rule>
<note>重写loign.jsp成login.html</note>
<!-- 对应controller中redireact的路径 -->
<from>login.html</from>
<!-- 对应实际工程中jsp文件 -->
<to type="forward">/login.jsp</to>
</rule>
</urlrewrite>
4.程序controller中的返回内容要与<from>中的内容一致,比如下列代码片返回值得要与urlrewrite中的一致:
@RequestMapping(value="http://www.mamicode.com/login.do")
public String login(HttpServletRequest request, HttpServletResponse response, Role role) throws Exception {
if (userService.selectRoleByNameAndPassword(role)) {
return "index";
} else {
return "redirect:login.html";
}
}
Spring URL重写