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MySLQ排序后标记排行

2024-09-17 12:36:26   221人阅读

查询排行及所有(表名.*)

1.

set @rownum=0;

SELECT @rownum:=@rownum+1 AS top, customer.*
FROM  customer

 

2.

SELECT @rownum:=@rownum+1 AS top, customer.* 
FROM (SELECT @rownum:=0) r, customer ORDER BY customer.this_month_cost DESC

1和2的结果：

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查询排行及id(表名.id)

SELECT @rownum:=@rownum+1 AS top, customer.id
FROM (SELECT @rownum:=0) r, customer ORDER BY customer.this_month_cost DESC

结果：

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排序后更新原表的排行：

UPDATE `customer` c,
 (
    SELECT
        @rownum :=@rownum + 1 AS rownum,
        customer.id
    FROM
        (SELECT @rownum := 0) r,
        customer
    ORDER BY
        customer.this_month_cost DESC
) a
SET c.top = a.rownum
WHERE
    c.id = a.id

 

MySLQ排序后标记排行


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