首页 > 代码库 > hdu-1001Sum Problem
hdu-1001Sum Problem
Sum Problem
Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 469658 Accepted Submission(s): 118388
Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1100
Sample Output
15050
水题一道，题意就是计算1~n的和，唯一需要注意的是格式问题，每两个输出数据之间要多上一个换行
贴上代码：
# include <stdio.h>int main (){ int sum,n; while(scanf("%d",&n)!=EOF) { sum=0; for(int i=1;i<=n;i++) { sum+=i; } printf("%d\n\n",sum); }}
hdu-1001Sum Problem
声明：以上内容来自用户投稿及互联网公开渠道收集整理发布，本网站不拥有所有权，未作人工编辑处理，也不承担相关法律责任，若内容有误或涉及侵权可进行投诉： 投诉/举报 工作人员会在5个工作日内联系你，一经查实，本站将立刻删除涉嫌侵权内容。