实现对一个目录下面（包含子目录下面）有一行包含过滤字符串就输出其文件名的绝对路径
  C:\python_fullstack_wen\day24\wen
"""

import time,os
#定义
def init(func):
    "装饰器"
    def wrapper(*args,**kwargs):
        res=func(*args,**kwargs)
        next(res)
        return res
    return wrapper

@init
def search(target):
    "找到目录下所有文件名的绝对路径"
    while True:
        dir_path=yield
        g=os.walk(dir_path)
        for i in g:
            for j in i[-1]:
                file_path="%s\\%s"%(i[0],j)
                target.send(file_path)
@init
def opener(target):
    "打开文件，返回文件句柄"
    while True:
        file_path=yield
        with open(file_path) as f:
            target.send((file_path,f))
@init
def cat(target):
    "查看文件，返回每行内容"
    while True:
        file_path,f=yield
        for line in f:
            target.send((file_path,line))
@init
def grep(pattern,target):
    "过滤这行，如果符合返回文件路径"
    while True:
        file_path,line=yield
        if pattern in line:
            target.send(file_path)
@init
def printer():
    "打印"
    while True:
        file_path=yield
        print(file_path)

#调用
g=search(opener(cat(grep("wenyanjie",printer()))))
g.send("C:\python_fullstack_wen\day24\wen")

import os

def search(dir_name, partten):
    g = os.walk(dir_name)
    for i in g:
        for j in i[-1]:
            file_path = i[0] + "\\" +j
            with open(file_path) as f:
                for line in f:
                    if partten in line:
                        print(file_path)

search("c:\\test", "python")