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F Takio与Blue的人生赢家之战
Time Limit:1000MS Memory Limit:65535K
题型: 编程题 语言: 无限制
描述
在那个风起云涌的SCAU ACM里，有两位人生赢家，他们分别是大洲Takio神和Blue神。 (尤其是blue神。)由于这两位人生赢家代码能力强，才高八斗，学富五车，英俊潇洒，玉树临风，独步江湖，呼风唤雨，妹子纷至沓来。而小邪由于太渣了，只能默默地帮他们记录下他们换了多少个妹子。以上背景纯属题目需要，其实两位大神是很专情的。终于有一天，小邪计算出他们身边妹子的总数n，想要给Takio神和Blue神。但是Takio神和Blue神的邮箱是使用英文的，而小邪的英语又很渣，于是无法将n翻译成英语发过去。但是，小邪想到了你——聪明的14级新生，向你寻求答案。出题人:K·小邪
输入格式
第一行是一个整数t(t <= 100)，代表样例个数对于每个样例有一个整数n(0<=n<=2000000000)
输出格式
对于每个n，输出其英文表现形式，具体格式见样例输出
输入样例
4512110101008611
输出样例
fiveone hundred and twenty-oneone thousand and tenone million, eight thousand, six hundred and eleven
Hint
输出不一定符合英语规范，但是要符合Sample的规范对于一个n>1000,若n%1000 >= 100(%代表取余操作)且不为0，且在n%1000对应的英文输出前（如果存在）用","相连而不是"and"需要用到的英文单词为(不包括引号)："zero","one","two","three","four","five","six","seven","eight","nine""ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen""twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety""hundred","thousand","million","billion"分别代表0,1,2,3,4,5,6,7,8,910,11,12,13,14,15,16,17,18,1920,30,40,50,60,70,80,90100,1000,1000000,1000000000
#include<stdio.h>#include<string.h>void go(void);int a[12],k,num;int leap,leap1,leap2,leap3,leap4,leap5,leap6,leap7,leap8,leap9,leap10;char str[100][100]={ "zero","one","two","three","four","five","six", "seven","eight","nine","ten","eleven","twelve", "thirteen","fourteen","fifteen","sixteen", "seventeen","eighteen","nineteen","twenty"};int main(){ int i,k,T; strcpy(str[30],"thirty"); strcpy(str[40],"forty"); strcpy(str[50],"fifty"); strcpy(str[60],"sixty"); strcpy(str[70],"seventy"); strcpy(str[80],"eighty"); strcpy(str[90],"ninety"); scanf("%d",&T); while(T--) { memset(a,0,sizeof(a)); leap=leap1=leap2=leap3=leap4=leap5=leap6=leap7=leap8=leap9=leap10=0; scanf("%d",&num); i=1; k=num; if(num>1000&&num%1000>=100) leap=1; while(k!=0) { a[i++]=k%10; k=k/10; } k=i-1; if(k==0||k==1) {printf("%s\n",str[num]);continue;} if(k==2) {if(num>0&&num<=20||num%10==0) printf("%s\n",str[num]); else printf("%s-%s\n",str[num-num%10],str[num%10]);continue;} go(); printf("\n"); } return 0;}void go(void){ int temp1,temp2,temp3; if(a[10]) {printf("%s billion",str[a[10]]);leap10=1;} if((leap&&k>=9)||(leap10&&a[9]!=0)||(leap10&&a[8]!=0)||(leap10&&a[7]!=0)||(leap10&&a[6]!=0)||(leap10&&a[5]!=0)||(leap10&&a[4]!=0)) printf(", "); if(a[9]) {printf("%s hundred",str[a[9]]);leap9=1;} temp1=a[8]*10+a[7]; if(leap9&&temp1!=0) printf(" and "); if(temp1!=0) { if((temp1>0&&temp1<=20)||temp1%10==0) printf("%s",str[temp1]); else printf("%s-%s",str[temp1-temp1%10],str[temp1%10]); leap7=1; } if(leap9||leap7) printf(" million"); if((leap&&k>=7)||((leap9&&a[6]!=0)||(leap7&&a[6]!=0))||((leap9&&a[5]!=0)||(leap7&&a[5]!=0))||((leap9&&a[4]!=0)||(leap7&&a[4]!=0))) printf(", "); if(a[6]) {printf("%s hundred",str[a[6]]);leap6=1;} temp2=a[5]*10+a[4]; if(leap6&&temp2!=0) printf(" and "); if(temp2!=0) { if((temp2>0&&temp2<=20)||temp2%10==0) printf("%s",str[temp2]); else printf("%s-%s",str[temp2-temp2%10],str[temp2%10]); leap4=1; } if(leap6||leap4) printf(" thousand"); if(leap) printf(", "); if(a[3]) {printf("%s hundred",str[a[3]]);leap3=1;} temp3=a[2]*10+a[1]; if((leap3&&temp3!=0)||(a[3]==0&&temp3!=0)) printf(" and "); if(temp3!=0) { if((temp3>0&&temp3<=20)||temp3%10==0) printf("%s",str[temp3]); else printf("%s-%s",str[temp3-temp3%10],str[temp3%10]); }}
F Takio与Blue的人生赢家之战
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