首页 > 代码库 > 1058. A+B in Hogwarts

1058. A+B in Hogwarts

1058. A+B in Hogwarts (20)

时间限制
50 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it‘s easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28
 1 #include<stdio.h> 2 #include<math.h> 3 #include<stdlib.h> 4 #include<string.h> 5  6 int main() 7 { 8     struct hog 9     {10         int g, s, k;11     };12     hog a, b, sum;13     sum.g = sum.s = sum.k = 0;14     scanf("%d.%d.%d %d.%d.%d", &a.g, &a.s, &a.k, &b.g, &b.s, &b.k);15     if(a.k + b.k < 29)16     {17         sum.k = a.k + b.k;18     }19     else20     {21         sum.k = a.k + b.k - 29;22         sum.s++;23     }24     if(sum.s + a.s + b.s < 17)25     {26         sum.s += a.s + b.s;27     }28     else29     {30         sum.s += a.s + b.s - 17;31         sum.g++;32     }33     sum.g += a.g + b.g;34     printf("%d.%d.%d\n", sum.g, sum.s, sum.k);35     return 0;36 }

 

1058. A+B in Hogwarts