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PAT1065. A+B and C (64bit)
Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C.
Input Specification:
The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.
Output Specification:
For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).
Sample Input:
31 2 32 3 49223372036854775807 -9223372036854775808 0
Sample Output:
Case #1: falseCase #2: trueCase #3: false
思路：此题有一点需要注意，以后不要在if里面进行计算因为可能有问题 ,需要开始个临时变量。
1 #include<cstdio> 2 int main(int argc, char *argv[]) 3 { 4 int T; 5 long long a; 6 long long b; 7 long long c; 8 scanf("%d",&T); 9 for(int i=1;i<=T;i++)10 {11 scanf("%lld%lld%lld",&a,&b,&c);12 bool flag;13 long long temp=a+b; //????????????? 14 if(a>0&&b>0&&temp<0)15 flag=true;16 else if(a<0&&b<0&&temp>=0) //?????17 flag=false;18 else if(temp>c)19 flag=true;20 else 21 flag=false;22 if(flag)23 printf("Case #%d: true\n",i);24 else 25 printf("Case #%d: false\n",i);26 }27 return 0;28 }
PAT1065. A+B and C (64bit)
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