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Jquery ajax 表单验证

jQuery异步请求大家都很熟悉,这里不再解释。直接上代码

jsp页面:

<%@ page language="java" import="java.util.*" pageEncoding="utf-8"%><%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%><%String path = request.getContextPath();String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><html>  <head>    <base href="<%=basePath%>">        <title>My JSP ‘ajax_form.jsp‘ starting page</title>        <meta http-equiv="pragma" content="no-cache">    <meta http-equiv="cache-control" content="no-cache">    <meta http-equiv="expires" content="0">        <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">    <meta http-equiv="description" content="This is my page">    <!--    <link rel="stylesheet" type="text/css" href="http://www.mamicode.com/styles.css">    -->    <!-- 引入jquery -->    <script type="text/javascript" src="${pageContext.request.contextPath }/js/jquery-1.9.1.js"></script>    <script type="text/javascript">        $(function(){            //alert($(‘#p‘).html());弹出具体的内容:hello                    });        function lost(){           //alert(‘失去焦点‘);           //alert($(‘#name‘)[0].value); 获取输入框的值,首先需要的到这个元素,这个元素是jquery对象,需要转为dom对象,使用数组下标的方法           $.ajax({                 url: "FromServlet",                 type:"post",                data:"name="+$(#name)[0].value+"&password=123",//向后台传送的数据格式                dataType:"json",                success: function(data, textStatus){                   //alert(data.password);                   //alert(data.name);                   //alert(textStatus);                   $("#td").after("<font color=‘red‘ fontsize=‘5‘>"+data.name+"用户名已经存在!</font>");                },                error:function(XMLHttpRequest, textStatus, errorThrown){                   alert(textStatus);                }           });                   }    </script>  </head>    <body>    <p id="p">hello</p>    <form action="">         <table>            <tr>            <td>用户名:</td>            <td id="td"><input type="text" name="name" onblur="lost()" id="name"/></td>            <tr>            <td>&nbsp;</td>            <td><input type="password" name="password"/></td>            </tr>            <tr>            <td><input type="submit" value="提交"/></td>            <td><input type="reset" value="重置"/></td>            </tr>         </table>    </form>  </body></html>

servlet后台代码;

package ajaxServlet;import java.io.IOException;import java.io.PrintWriter;import javax.servlet.ServletException;import javax.servlet.http.HttpServlet;import javax.servlet.http.HttpServletRequest;import javax.servlet.http.HttpServletResponse;import net.sf.json.JSONObject;public class FromServlet extends HttpServlet {    /**     * Constructor of the object.     */    public FromServlet() {        super();    }    /**     * Destruction of the servlet. <br>     */    public void destroy() {        super.destroy(); // Just puts "destroy" string in log        // Put your code here    }    /**     * The doGet method of the servlet. <br>     *     * This method is called when a form has its tag value method equals to get.     *      * @param request the request send by the client to the server     * @param response the response send by the server to the client     * @throws ServletException if an error occurred     * @throws IOException if an error occurred     */    public void doGet(HttpServletRequest request, HttpServletResponse response)            throws ServletException, IOException {        response.setContentType("text/html");        PrintWriter out = response.getWriter();    }    /**     * The doPost method of the servlet. <br>     *     * This method is called when a form has its tag value method equals to post.     *      * @param request the request send by the client to the server     * @param response the response send by the server to the client     * @throws ServletException if an error occurred     * @throws IOException if an error occurred     */    public void doPost(HttpServletRequest request, HttpServletResponse response)            throws ServletException, IOException {        //response.setContentType("text/html");        response.setCharacterEncoding("utf-8");        String name = request.getParameter("name");        String password = request.getParameter("password");        System.out.println("你输入的是="+name);        System.out.println("你输入的密码是="+password);        PrintWriter out = response.getWriter();        //String json = "{\"success\":\"你好\",\"type\":\"succ\"}";        //out.println(json);        //JSON对象 使用这种方法不用拼装json格式就可以自动转为json数据,不过要导入相应的jar文件,共六个        JSONObject jsonObject = new JSONObject();        jsonObject.accumulate("password", password).accumulate("name", name);        response.setContentType("application/json");        response.getWriter().write(jsonObject.toString());    }    /**     * Initialization of the servlet. <br>     *     * @throws ServletException if an error occurs     */    public void init() throws ServletException {        // Put your code here    }}

 

Jquery ajax 表单验证