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252 Meeting Rooms
Given an array of meeting time intervals consisting of start and end times [[s1,e1],[s2,e2],...] (si < ei),
determine if a person could attend all meetings. For example, Given [[0, 30],[5, 10],[15, 20]], return false.
Implement a Comparator<Interval>
Syntax: don‘t forget the public sign when defining a function
/** * Definition for an interval. * public class Interval { * int start; * int end; * Interval() { start = 0; end = 0; } * Interval(int s, int e) { start = s; end = e; } * } */ public class Solution { public boolean canAttendMeetings(Interval[] intervals) { if (intervals==null || intervals.length==0 || intervals.length==1) return true; Comparator<Interval> comp = new Comparator<Interval>() { public int compare(Interval i1, Interval i2) { return (i1.start==i2.start)? i1.end-i2.end : i1.start-i2.start; } }; Arrays.sort(intervals, comp); Interval pre = intervals[0]; for (int i=1; i<intervals.length; i++) { Interval cur = intervals[i]; if (cur.start < pre.end) return false; pre = cur; } return true; } }
public static <T> void sort(T[] a, Comparator<? super T> c)
- 根据指定比较器产生的顺序对指定对象数组进行排序。
252 Meeting Rooms
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